Find Acceleration of Blocks on Table [SOLVED]

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SUMMARY

The discussion focuses on solving the acceleration of two blocks, A and B, with weights of 5 lbs and 6 lbs respectively, and a friction coefficient of 0.3. The user initially set up the equations incorrectly, defining both accelerations as positive when they should have been defined with opposite signs. The correct relationship derived from dependent motion is aa = 2ab, which accounts for the direction of motion. The user was advised to adjust the sign of the acceleration of block B to achieve the correct results.

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[SOLVED] Block on a table

Homework Statement



http://img91.imageshack.us/img91/4285/fudgepq5.th.png

I am having some trouble finding the acceleration of the blocks, can anyone help me?

The weight of B is 6 lbs.
The weight of A is 5 lbs.
The friction coef is .3

Homework Equations


The Attempt at a Solution



1) The positive y-axis goes from left to right
sum of forces in y = (6/32)*ab = 2T - 1.8

2) positive y-axis goes from top to bottom
sum of forces in y = (5/32)*aa = 5-T

I know that aa = -2ab
The way my book derives the relationship between aa and ab is from 'dependent motion' they say that length = sa + 2sb and taking the time derivative twice is 0 = aa + 2ab, the problem is with the way I have my equations setup, when i use aa = -2ab i get the wrong answer, does anyone know how I can fix it so I am using aa = -2ab and getting the correct answer?
I don't see anything wrong with my equations, but i am getting the wrong accelerations. Can anyone help?
 
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sign problems

jesuslovesu said:
I know that aa = -2ab
Not exactly. You've defined both aa and ab to be positive when B moves right and A moves down, so it should be: aa = 2ab.
The way my book derives the relationship between aa and ab is from 'dependent motion' they say that length = sa + 2sb and taking the time derivative twice is 0 = aa + 2ab,
That's fine, but realize that you are defining the position of B to increase to the right, but sb actually decreases when mass B moves to the right. That's why you need to change the sign.
 

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