Find Acceleration with an angle

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SUMMARY

The discussion focuses on calculating the acceleration of a box being pulled by a clerk with a force of 185.0 N at an angle of 25.0 degrees. The box has a mass of 35.0 kg and a coefficient of kinetic friction of 0.450. To find the acceleration, one must analyze the forces acting on the box, including the normal force and frictional force. The net force, after accounting for these factors, divided by the mass of the box yields the acceleration.

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  • Understanding of Newton's laws of motion
  • Knowledge of force diagrams and vector components
  • Familiarity with the concept of friction and its coefficient
  • Basic algebra for solving equations
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  • Study the calculation of net forces in inclined plane problems
  • Explore the effects of friction on motion, particularly kinetic friction
  • Practice solving problems involving forces and acceleration using Newton's second law
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1. A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 185.0 N at an angle of 25.0 degrees with the floor. The box has a mass of 35.0 kg, and the coefficient of kinetic friction is 0.450. Find the Acceleration of the box.



Homework Equations


Find the accerlation.

3. I have no idea how to do this. please help!
 
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MusicalAyame0 said:
1. A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 185.0 N at an angle of 25.0 degrees with the floor. The box has a mass of 35.0 kg, and the coefficient of kinetic friction is 0.450. Find the Acceleration of the box.



Homework Equations


Find the accerlation.

3. I have no idea how to do this. please help!

Welcome to PF.

Draw a force diagram. The normal force of the weight looks like it will be offset by the vertical up component of the force.

So that leaves the net normal force down times the coefficient of friction opposing the horizontal component of the force. That net force divided by the mass gives you the acceleration.
 
Thanks!
 

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