Find All Subgroups of U(14) in $\mathbb{Z}_{14}$

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SUMMARY

The discussion focuses on identifying all subgroups of U(14), the group of units of $\mathbb{Z}_{14}$. The group U(14) consists of the elements {1, 3, 5, 9, 11, 13} with multiplication modulo 14 as the operation. The group is confirmed to be cyclic and abelian, with a total of four distinct subgroups: one of order 1, one of order 2, one of order 3, and one of order 6. Each subgroup is generated by a single element, with a recommendation to first identify a generator of order 6.

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  • Understanding of group theory concepts, specifically cyclic and abelian groups.
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  • Knowledge of subgroup generation and the classification of groups by order.
  • Basic experience with the structure of the group of units in modular arithmetic.
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This discussion is beneficial for students and enthusiasts of abstract algebra, particularly those studying group theory, as well as educators looking for examples of cyclic groups and their properties.

alexmahone
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Find all subgroups of U(14), the group of units of $\mathbb{Z}_{14}$.

My attempt:

U(14)={1, 3, 5, 9, 11, 13} and the operation is multiplication modulo 14. Do I just find the subgroups generated by each of the elements in U(14)? What about subgroups generated by two elements?
 
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You have an abelian group of order $6$. There are, up to isomorphism, only two groups of order $6$, and only one of those is abelian. Thus, your group is cyclic.

This means you have exactly:

1 group of order 1
1 group of order 2
1 group of order 3
1 group of order 6

each of which will be generated by a single element. I suggest finding a generator (element) of order 6, first.
 

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