MHB Find All Subgroups of U(14) in $\mathbb{Z}_{14}$

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The group of units U(14) consists of the elements {1, 3, 5, 9, 11, 13} with multiplication modulo 14. To find all subgroups, one should identify those generated by each element, as well as consider combinations of two elements. U(14) is an abelian group of order 6, which is cyclic, indicating that it has a specific structure. There are four distinct subgroups: one of order 1, one of order 2, one of order 3, and one of order 6, each generated by a single element. Finding a generator of order 6 is a crucial step in identifying these subgroups.
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Find all subgroups of U(14), the group of units of $\mathbb{Z}_{14}$.

My attempt:

U(14)={1, 3, 5, 9, 11, 13} and the operation is multiplication modulo 14. Do I just find the subgroups generated by each of the elements in U(14)? What about subgroups generated by two elements?
 
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You have an abelian group of order $6$. There are, up to isomorphism, only two groups of order $6$, and only one of those is abelian. Thus, your group is cyclic.

This means you have exactly:

1 group of order 1
1 group of order 2
1 group of order 3
1 group of order 6

each of which will be generated by a single element. I suggest finding a generator (element) of order 6, first.
 
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