ABC is an isosceles triangle such that
AB = AC
A has coordinates (4, 37)
B and C lie on the line with equation 3y = 2x + 12
Find an equation of the line of symmetry of triangle ABC.
Give your answer in the form px + qy = r where p, q and r are integers. Show clear algebraic working.
The Attempt at a Solution
Would the equation of the line of symmetry of triangle ABC be y = -3/2 x + c (as it's perpendicular to y=2/3x + 4)
So as it goes through A (4,37) we get y = -3/2 x + 43
How on earth do you get the form px + qy = r