- #1
Kartik.
- 55
- 1
Taking a general function with two quadratic eqs,
Y = (ax^2+bx+c / px^2+qx+r)
ax+bx+c = pyx^2+qxy+ry
x^2(a-py) + x(b-qy)+(c-ry)=0
The discriminant turns out to be a+ve or a 0.
So,
(b-qy)^2 - 4(a-py)(c-ry) >or= 0
Now how does this equation yield a range for y?or can it?what are the next steps?
Y = (ax^2+bx+c / px^2+qx+r)
ax+bx+c = pyx^2+qxy+ry
x^2(a-py) + x(b-qy)+(c-ry)=0
The discriminant turns out to be a+ve or a 0.
So,
(b-qy)^2 - 4(a-py)(c-ry) >or= 0
Now how does this equation yield a range for y?or can it?what are the next steps?