Find angle, given the tension of the rope.

Click For Summary
SUMMARY

The discussion focuses on calculating the angle θ between a cart and a string given the tension in the rope and the forces acting on two carts with sensors. The measurements provided are F1 = 16.32 N and F2 = 17.03 N, with a cart mass of 457.3 g. The participant attempted to use the equation T = mgsinθ to derive the angle but expressed confusion over the relevance of gravitational force (g) in this context, as the sensors are not suspended. The correct approach involves recognizing that the angle can be derived from the tension and the weight of the cart using trigonometric relationships.

PREREQUISITES
  • Understanding of basic physics concepts including tension and forces.
  • Familiarity with trigonometric functions, particularly sine.
  • Knowledge of Newton's second law (F = ma).
  • Ability to manipulate equations involving gravitational force (g = 9.8 m/s²).
NEXT STEPS
  • Study the derivation and application of the tension formula T = mgsinθ in various contexts.
  • Learn how to apply trigonometric identities to solve for angles in physics problems.
  • Explore examples of tension problems involving multiple forces and angles.
  • Review Newton's laws of motion to understand the relationship between mass, force, and acceleration.
USEFUL FOR

This discussion is beneficial for college students studying introductory physics, particularly those tackling problems involving forces and tension in systems with multiple objects. It is also useful for anyone seeking to improve their understanding of trigonometry in physical applications.

brikayyy
Messages
15
Reaction score
0

Homework Statement



PROBLEM: Choose a pair of measurements of the forces from parts A5, A6, or A7, where the forces on the sensors were quite different. Imagine there was an angle between one cart and the string. Assuming that the larger force was the true tension in the string, what is the angle θ?

DIAGRAM (GIVEN):

bN5aNVX.png


INFORMATION:

M (of a cart with the sensor) = 457.3 g
F1 (Cart One) = 16.32 N
F2 (Cart Two) = 17.03 N

CONTEXT: This is for a lab conclusion I have to write. For the parts A5 - A7 mentioned in the problem below, those were all sections of the lab where we "played tug-of-war" with carts that had force sensors taped to them. The forces I chose are from when two people of equal mass lifted the carts and did tug-of-war, one for each cart.

Homework Equations



F = ma (?)
T = mgsinθ (?)

The Attempt at a Solution



At first, I thought I could do a simple trigonometry problem, but then I realized that I probably read the problem incorrectly.

I tried to work backwards with T = mgsinθ? So...

T/mg = sinθ
17.03 / ( 457.3 * 9.8 ) = 0.00380003302
0.00380003302 = sinθ
sin-1(0.00380003302) = 0.217726378062

But that seems really off to me... Now I have no idea what to do. Thanks so much for your time!

4. Personal Information

I am a college freshman-sophomore (going into sophomore year and taking summer school classes) taking a basic level Physics class. I have never taken physics in my life prior to this; neither am I good at math. I am simultaneously taking Calculus II right now.
 
Physics news on Phys.org
hi brikayyy! welcome to pf! :smile:

what does g have to do with it? :wink:

(or m ?)​
 
tiny-tim said:
hi brikayyy! welcome to pf! :smile:

what does g have to do with it? :wink:

(or m ?)​

Thanks!

I thought g was significant because you had the two sensors at an angle, basically one hanging off the other. But now I thought about it and this isn't the same as some other tension problems I've seen where one object is suspended in the air by a string. I'm assuming this censor is lying flat on a surface?

I admit I initially didn't think mass was significant, but I didn't know how to do a tension problem, so I tried to look up the formula for tension. I'm not sure if the same logic as I just explained above applies here, that it's not important because the sensor is not hanging off the other one?
 

Similar threads

Replies
44
Views
3K
Replies
2
Views
1K
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 39 ·
2
Replies
39
Views
7K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
9K
  • · Replies 3 ·
Replies
3
Views
3K