Find Approx Wavelength of Titanium Kbeta X-Rays

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SUMMARY

The discussion focuses on calculating the approximate wavelength of K-beta X-rays emitted by titanium. The key concept involves understanding the transition of an electron from the n=3 shell to the n=1 shell, with the effective nuclear charge (Z_eff) being crucial for accurate energy level calculations. The relevant equation for energy levels is E_n = -Z^2 (13.6 eV/n^2), which must be adjusted for non-hydrogenic atoms by incorporating Z_eff. This approach allows for the determination of energy differences necessary for calculating the wavelength of emitted X-rays.

PREREQUISITES
  • Understanding of atomic structure and electron shells
  • Familiarity with the concept of effective nuclear charge (Z_eff)
  • Knowledge of energy level equations for hydrogenic atoms
  • Basic principles of X-ray emission and transitions
NEXT STEPS
  • Research the calculation of effective nuclear charge (Z_eff) for multi-electron atoms
  • Study the derivation and application of the energy level equation E_n = -Z^2 (13.6 eV/n^2)
  • Explore the principles of X-ray spectroscopy and its applications in material science
  • Learn about the differences between hydrogenic and non-hydrogenic atoms in quantum mechanics
USEFUL FOR

Students and professionals in physics, particularly those studying atomic physics, X-ray spectroscopy, and quantum mechanics, will benefit from this discussion.

negatifzeo
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Homework Statement


The X-ray spectrum for a typical metal is shown in Figure 31-22. Find the approximate wavelength of Kbeta X-rays emitted by titanium. (Hint: An electron in the M shell is shielded from the nucleus by the single electron in the K shell, plus all the electrons in the L shell.)
(The figure seems irrelevant to me, no useful data is privded by it, it's just a graph with no labels.)

Homework Equations





The Attempt at a Solution



I don't really know what to do here, there's several things I don't understand. I believe that K-beta X-rays are emitted when the electron drops from the 3rd excited state to the ground level. But how do you determine the energy level difference here? And when Titanium is in an "excited" state, does that mean that just one electron moved up 3 levels, or more than one? Any help in explaining this would be greatly appreciated.
 
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Hi negatifzeo,

That's right; in this case, there is only one electron in the n=1 shell, and one of the electrons that is in the n=3 shell is dropping to fill the n=1 shell.

If this was a hydrogenic titanium atom with only one electron, and the electron was making a transition from n=3 to n=1, the energy levels would be found from:

<br /> E_n = -Z^2 \frac{13.6\mbox{ eV}}{n^2}<br />

If the atom is not hydrogenic, then the equation above has to modified to account for the other electrons. The inner electrons will partly shield the nuclear charge. We account for this in the above equation by changing Z\to Z_{\rm eff}, where Z_{\rm eff} is called the effective nuclear charge.

So mostly what this problem is about is that you need to find the effective Z values for an electron in the n=3 shell and for an electron in the n=1 shell of titanium.

Does this help?
 

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