ineedhelpnow said:find the arc length function for the curve $y=2x^{3/2}$ with starting point $P_{0}(1,2)$. how do i do this? this is what I've done so far.
$y'=3\sqrt{x}$
$1+(3\sqrt{x})^2=9x+1$
$\int_{a}^{b} \ \sqrt{9x+1}\,dx$
what's my a and what's my b?
ineedhelpnow said:ooookay! thanks! so i do it from 1 to x?
Arc length starting from P0 is the distance along the circumference of a circle from the point P0 to another point on the circle.
The formula for calculating arc length starting from P0 is L = rθ, where L is the arc length, r is the radius of the circle, and θ is the angle in radians between the two points on the circle.
No, the arc length starting from P0 cannot be greater than the circumference of the circle. The maximum arc length is equal to the circumference of the circle, which is found by multiplying the diameter by π.
The location of P0 does not affect the arc length. The arc length starting from P0 is determined by the angle and radius, not the position of the point on the circle.
No, the arc length starting from P0 cannot be negative. It is always a positive value, as it represents a distance along the circumference of a circle.