Find Change in Charge of Identical Capacitors w/ Dielectric Insertion

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Homework Help Overview

The discussion revolves around two identical capacitors connected in series with a fixed potential difference, where one capacitor has a dielectric slab inserted. The problem seeks to determine the change in charge on each capacitor due to the dielectric insertion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between capacitance, charge, and potential, questioning which capacitor the dielectric is inserted into and how it affects the overall charge.

Discussion Status

Some participants have suggested using the formula Q = CV to analyze the situation, while others are considering the equivalent capacitance of the series configuration. There is an ongoing exploration of how the dielectric affects the charge on the capacitors.

Contextual Notes

The problem involves a fixed total potential and specific dielectric properties, which may influence the calculations and assumptions made by participants.

Winzer
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Homework Statement


Two identical capacitors and of capacitance 1.20 F are connected in series across a FIXED total potential of 650 V. A dielectric slab of dielectric constant 3.70 can fill and is slowly inserted into that capacitor.
1. What is the change in charge, , on when the dielectric is added to ?
2. What is the change in charge, , on when the dielectric is added to ?

Homework Equations


[tex]C=C_{o}K[/tex]

The Attempt at a Solution


Not quite sure.
 
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Use Q = CV. which capacitor is the dielectric inserted into?
 
the first one
 
Winzer said:
the first one

What is the equivalent capacitance of the two series capacitors? Use the Q=CV relationship to get the charge on the equivalent capacitor...

The charge on each capacitor is the same as the charge you get above...
 

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