Find change in electric potential energy

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A uniform electric field of 4.1 × 10^5 N/C is directed along the positive x-axis, and the task is to find the change in electric potential energy for a +5.3 µC charge moving from the origin to specified points. The correct approach involves using the formula ΔV = -E·Δs, which accounts for the direction of the electric field and the displacement. Caution is advised as the formula requires a dot product rather than a scalar product, and integration may be necessary for accurate calculations. It is noted that the answers for points (b) and (c) will be the same, while (a) will yield a different result. This discussion emphasizes the importance of understanding the context of electric potential energy in relation to external electric fields.
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Homework Statement


A uniform electric field of magnitude 4.1 ✕ 10^5 N/C points in the positive x-direction. Find the change in electric potential energy of a +5.3 µC charge as it moves from the origin to each of the points given below.
(a) (0, 6.9 m)
__ J

(b) (6.9 m, 0)
__J

(c) (6.9 m, 6.9 m)
__J

Homework Equations


I'm confused by the phrase electric potential energy. I was thinking I should use V= k|q|/r^2 but was then confused. Electric potential is V=kq/r so should I maybe just do that for an initial and final on each? Some research made it sound like I would use ( ∆V = -E*∆s ). Can someone help me as to which direction I should go?

The Attempt at a Solution

 
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The correct direction is towards the use of formula ##\Delta V=-E\Delta s## because the other formula you mention (V=Kq/r) is for the potential energy of the charge due to the field that charge itself creates . But here we are asked for the potential energy due to the external electric field.

However you need to be careful on the use of ##\Delta V=-E\Delta s## because it is in an oversimplified form. The correct form of the formula has dot product and not simple scalar product (and also the use of integral in front of the product).

To give an additional tip, the answer for b) and c) is the same but the answer for a) is different.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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