Find change in electric potential energy

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SUMMARY

The discussion focuses on calculating the change in electric potential energy for a +5.3 µC charge moving in a uniform electric field of 4.1 × 10^5 N/C. The correct approach involves using the formula ΔV = -E·Δs, which accounts for the direction of the electric field and the displacement. It is emphasized that the formula should include the dot product for accuracy, rather than a simple scalar product. The answers for points (b) and (c) are identical, while point (a) yields a different result.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with electric potential energy concepts
  • Knowledge of vector operations, specifically dot products
  • Basic proficiency in physics equations related to electric forces
NEXT STEPS
  • Study the derivation and application of the formula ΔV = -E·Δs in electric fields
  • Learn about the differences between electric potential (V) and electric potential energy (U)
  • Explore the implications of vector calculus in physics, particularly in electric fields
  • Investigate the use of integrals in calculating work done by electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone looking to deepen their understanding of electric potential energy and its calculations in uniform electric fields.

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Homework Statement


A uniform electric field of magnitude 4.1 ✕ 10^5 N/C points in the positive x-direction. Find the change in electric potential energy of a +5.3 µC charge as it moves from the origin to each of the points given below.
(a) (0, 6.9 m)
__ J

(b) (6.9 m, 0)
__J

(c) (6.9 m, 6.9 m)
__J

Homework Equations


I'm confused by the phrase electric potential energy. I was thinking I should use V= k|q|/r^2 but was then confused. Electric potential is V=kq/r so should I maybe just do that for an initial and final on each? Some research made it sound like I would use ( ∆V = -E*∆s ). Can someone help me as to which direction I should go?

The Attempt at a Solution

 
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The correct direction is towards the use of formula ##\Delta V=-E\Delta s## because the other formula you mention (V=Kq/r) is for the potential energy of the charge due to the field that charge itself creates . But here we are asked for the potential energy due to the external electric field.

However you need to be careful on the use of ##\Delta V=-E\Delta s## because it is in an oversimplified form. The correct form of the formula has dot product and not simple scalar product (and also the use of integral in front of the product).

To give an additional tip, the answer for b) and c) is the same but the answer for a) is different.
 

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