Find charge density rho of a uniform shpere with radius R

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SUMMARY

The charge density ρ of a uniformly charged sphere with radius R and total charge q is defined as ρ = 3q / (4πR³). This formula is derived from the total charge divided by the volume of the sphere. The discussion also highlights the need to differentiate between the charge density inside (0 < r < R) and outside (r > R) the sphere, emphasizing that the charge density remains constant within the sphere and is zero outside. The integral approach used to find the potential V(r) is based on the charge density and requires careful consideration of the limits of integration.

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Andrew11
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Homework Statement


Find the potential V(r) inside and outside of a uniformly charged sphere with radius R and total charge q.
A) Fix first the charge density ρ(r) in the two regions 1: r>R and 2: 0<r<R the results should only be in terms of q and R[/B]

Homework Equations


ρ= qtot/Vtot
dq= ρ*Venc

The Attempt at a Solution


ρ= qtot/(4/3)piR^3
dq = [(qtot/(4/3)piR^3)*(4/3)pir^3]dr⇒(q*r^3/R^3)
∫dq = ∫q*(r^3/R^3)dr⇒ q*(¼r^4/R^3)

not sure if this is the correct approach to the problem
 
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ρ= qtot/(4/3)piR^3
Don't forget brackets: ρ= qtot/((4/3)piR^3) or ##\rho = \frac{3q}{4\pi R^3}##. Also, is this the charge density everywhere?
I don't understand what you are trying to do in the two lines below. You found the charge density, what does the integral mean and why do you integrate over a charge?
 

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