Find Closest Point on Hyperbola: xy=8 to (3,0)

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SUMMARY

The discussion focuses on finding the point on the hyperbola defined by the equation xy=8 that is closest to the point (3,0). The approach involves rewriting the hyperbola equation as y = 8/x, which allows for the formulation of a distance function D in terms of a single variable. The distance function is expressed as D = 2rtx^2 - 6x + 9 + 64/x^2, where the variables r and t are not clearly defined in the context of the problem. The goal is to minimize this distance function to identify the closest point on the hyperbola.

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  • Understanding of hyperbolas and their equations, specifically xy=8.
  • Knowledge of distance formulas in a Cartesian coordinate system.
  • Familiarity with calculus concepts, particularly minimization techniques.
  • Ability to manipulate algebraic expressions and functions.
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  • Study the properties of hyperbolas, focusing on the equation xy=8.
  • Learn about distance minimization in calculus, including derivative applications.
  • Explore how to derive distance functions from coordinate points.
  • Investigate the role of variables in distance equations and their significance.
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Students studying calculus, mathematicians interested in optimization problems, and educators seeking examples of hyperbola applications in real-world scenarios.

karisrou
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1) Find the point on the hyperbola xy=8 closest to (3,0).

I honestly, have no idea what to do. I seriously do not remember discussing anything like this in class, nor having any previous problems in homework. If anyone can give me a start or walkthrough, that would be fantastic!
 
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Well, y = 8/x gives you a relation between the two variables that allows you to write the distance from (x,y) to (3,0) in terms of one variable, which can then be easily minimized.
 
I've got D = 2rtx^2 - 6x + 9 + 64/x^2

I'm not sure as to how this minimizes?
 
HOW did you get that? What are r and t? What is D? There were not "r", "t", or "D" in your orginal statement of the problem.
 

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