Find Coefficient of Friction: Grindstone Problem

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SUMMARY

The discussion focuses on calculating the coefficient of friction for a grindstone problem involving a solid disk with a diameter of 0.530 meters and a mass of 50.0 kg, which is rotating at 830 rad/s. The user applies a normal force of 260 N against the rim, causing the grindstone to come to rest in 7.80 seconds. Key concepts discussed include rotational dynamics and the kinetic energy equation K = 1/2 M(Vcm)^2 + 1/2 (Icm) W^2, with emphasis on the condition of the center of mass being stationary.

PREREQUISITES
  • Understanding of rotational dynamics
  • Familiarity with kinematic equations for rotational motion
  • Knowledge of the moment of inertia (Icm) for solid disks
  • Basic principles of friction and normal force
NEXT STEPS
  • Calculate the moment of inertia for a solid disk using I = 1/2 M R^2
  • Learn how to derive the coefficient of friction from the deceleration of the grindstone
  • Explore the relationship between torque, angular acceleration, and frictional force
  • Study the application of energy conservation principles in rotational motion
USEFUL FOR

This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the principles of rotational dynamics and friction in practical applications.

Arielf04
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Please give me a hint on what should I follow in order to solve the problem I am stuck and have no clue :confused:

A grindstone in the shape of a solid disk with diameter 0.530 and a mass of = 50.0 is rotating at = 830 . You press an ax against the rim with a normal force of = 260 , and the grindstone comes to rest in 7.80 .

Find Coefficient of friction between the axe and the grinding stone.
 
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Do you know any rotational dynamics, specifically kinematic equations of such?
 
Well this is what I know

K= 1/2 M(Vcm)^2 + 1/2 (Icm) W^2

Since the center of mass is not moving then?

K=1/2 (Icm) W^2?
 

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