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seichan
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[SOLVED] Contact Force
a.Two blocks are in contact on a frictionless table. A horizontal force F Is applied to M2. The force's magnitude is 4 N. [The diagram shows the force pushing on the left side of M2, which has M1 on its right side.]If M1=1.09 kg, M2=3.02 kg, find the magnitude of the contact force between the two blocks.
b. If instead an equal but oppositely directed force -F is applied to M1 rather than M2, find the magnitude of the contact force between the two blocks.
Alright, right now we're doing Newton's laws of motion, so I'm pretty sure that F=ma is the only relevant equation.
We barely brushed upon contact forces and they are not mentioned in our book that I have seen. I checked wikipedia (I know...) and it informed me that when there are two masses and the force is being applied to mass A, then the contact force will be proportional to Mass B. Thus, I went with the assumption that I could do this:
F=M2*A
F/M2=A
A= 4/3.02 m/s^2
I figured I could then apply this to the second block.
F=M1A
F=4.36/4.02 N
I inputted this and it was incorrect. So, I figured that it perhaps was the difference between the two forces. This answer (2.9154) was incorrect as well. I have not even tried part b yet, knowing that the method involved is the same. I went to study group on Tuesday and the group leader claimed that it would just be 4 N. As you can probably guess, that is incorrect as well. Any help you can give would be very appreciated.
Homework Statement
a.Two blocks are in contact on a frictionless table. A horizontal force F Is applied to M2. The force's magnitude is 4 N. [The diagram shows the force pushing on the left side of M2, which has M1 on its right side.]If M1=1.09 kg, M2=3.02 kg, find the magnitude of the contact force between the two blocks.
b. If instead an equal but oppositely directed force -F is applied to M1 rather than M2, find the magnitude of the contact force between the two blocks.
Homework Equations
Alright, right now we're doing Newton's laws of motion, so I'm pretty sure that F=ma is the only relevant equation.
The Attempt at a Solution
We barely brushed upon contact forces and they are not mentioned in our book that I have seen. I checked wikipedia (I know...) and it informed me that when there are two masses and the force is being applied to mass A, then the contact force will be proportional to Mass B. Thus, I went with the assumption that I could do this:
F=M2*A
F/M2=A
A= 4/3.02 m/s^2
I figured I could then apply this to the second block.
F=M1A
F=4.36/4.02 N
I inputted this and it was incorrect. So, I figured that it perhaps was the difference between the two forces. This answer (2.9154) was incorrect as well. I have not even tried part b yet, knowing that the method involved is the same. I went to study group on Tuesday and the group leader claimed that it would just be 4 N. As you can probably guess, that is incorrect as well. Any help you can give would be very appreciated.
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