Find Current I1 in 7.5 Ω Resistor with Kirchhoff's Rule

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SUMMARY

The current I1 through the 7.5 Ω resistor in the given circuit is definitively calculated to be 0.65 A using Kirchhoff's Rule. The approach involves finding the equivalent resistance between points A & B and A & C, followed by breaking down the total current into I1 and I2 based on the parallel resistances. The solution confirms that the method applied is correct, leading to the expected result of 0.65 A.

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  • Understanding of Kirchhoff's Voltage Law
  • Knowledge of equivalent resistance calculations
  • Familiarity with series and parallel resistor configurations
  • Basic circuit analysis skills
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Homework Statement


In the circuit below: (a) Find the current I1 that passes through the 7.5 Ω resistor.



Homework Equations



Kirchhoff's Rule--Loops

The Attempt at a Solution


This was a problem in my textbook. The answer is .65 A, but I don't understand how to get that. I tried Kirchhoff's rule by finding equivalent R between A & B and Then finding equivalent R between A & C then finding I, Then breaking I into I1 and I2 (according to the parallel resistances between A & B)

However, I still didn't get the answer, .65 A. Was my approach correct, or is there another way? Thank you.
 

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Your plan of how to solve it is OK, and when I did it that way I got 0.65A.

If you can't find your mistake, show your working, then somebody can check through it.
 

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