# Find current with give volts and kWh

1. Mar 11, 2009

### cwesto

1. The problem statement, all variables and given/known data

A typical American family uses 800 kWh of electricity a month.
What is the average current in the 120 V power line to the house?

2. Relevant equations

P=IV

3. The attempt at a solution

800kW=800000W
800000=120I
I=$$\frac{800000}{120}$$

I'm getting this answer as incorrect. I'm not sure what to do from here. Help Please, Thanks!

2. Mar 11, 2009

### mgb_phys

kWH is a measure of energy = kW (power) * hours (time)

3. Mar 11, 2009

### cwesto

so how do I get from kWh to W?

4. Mar 11, 2009

### mgb_phys

1KWh is 1Kw for 1 hour.
If they use a total of 800 kWhours for the whole month, how much do they use each hour?

hint - how many hours in a month?

5. Mar 11, 2009

### cwesto

approx. 30.44 days in a month 30.44*24=730.56 hours in a month. 800000Wh/730.56h = 1095 W! oh... lol. DUH! Thanks! :D