DC Volts & Amps to Recharge 8.8 kWh Chevy Volt in 15 Min

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SUMMARY

The discussion focuses on determining the optimal combination of DC volts and amps required to recharge an 8.8 kWh Chevy Volt battery in 15 minutes using a Class III battery charger. The key equation used is P = IV, where power (P) is calculated by multiplying current (I) in amps by voltage (V) in volts. To achieve the desired charging time, the calculation indicates that a higher voltage with lower current is preferable to minimize power loss due to resistance in the circuit.

PREREQUISITES
  • Understanding of electrical power equations (P = IV)
  • Knowledge of DC circuit principles
  • Familiarity with battery charging specifications
  • Basic concepts of resistance and power loss in electrical systems
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  • Research optimal charging voltages for electric vehicle batteries
  • Learn about Class III battery charger specifications and capabilities
  • Investigate the effects of resistance on DC circuits
  • Explore advanced battery management systems for electric vehicles
USEFUL FOR

Electrical engineers, automotive engineers, and anyone involved in electric vehicle charging technology will benefit from this discussion.

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Homework Statement



The fastest, most powerful Class III battery charger available is supposed to recharge 8.8 kWh into a Chevy Volt battery pack in 15 minutes. What is the most likely combination of DC volts and amps to do this and why?

Homework Equations



W=VxI (I = amps)
a 120 V unit can do 12 I in 6 hours

The Attempt at a Solution

 
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If I remember correctly, P = IV (not the work, but the rate of work -- power). That would mean that you would have 8.8 [kWh]/15 [min] = I*V (be sure to convert the units appropriately). For DC circuits, I would assume the most likely condition would be the one with an appropriately large V/I ratio (more voltage and less current would imply less power loss from resistance).
 

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