Find de Broglie Wavelength of 7.0 eV Electron

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Homework Help Overview

The discussion revolves around finding the de Broglie wavelength of a 7.0 eV electron, focusing on the relationship between energy, velocity, and wavelength in quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore how to derive the velocity of the electron from its energy, questioning the use of the photoelectric effect equation and its relevance to the problem. There is discussion about whether to apply relativistic or non-relativistic formulas for kinetic energy.

Discussion Status

Some participants have expressed confusion about the relationship between kinetic energy and the work function, while others have suggested setting the kinetic energy equal to the given energy in eV. There are varying interpretations of the problem's context, with some questioning the applicability of the photoelectric effect.

Contextual Notes

Participants note a lack of examples in their study materials regarding de Broglie wavelength problems, which contributes to their uncertainty in applying the relevant equations.

Dart82
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Homework Statement


Find the de Broglie wavelength of a 7.0 eV electron.

Homework Equations


de Broglie wavelength = h/p = h/(mv)
Photoelectric effect equation (not 100% sure)

The Attempt at a Solution


i need to solve for v in de Broglie's equation so i can find the wavelength. i know the mass of the electron is 9.11x10^-31kg, i know that h is Plancks constant, and i know that the work function = 7.0 x (1.602x10^-19 J) BUT how can i find v?

I tried to find v by using the photoelectric effect equation but i didnt get a correct answer:
hf = KE + Work function...BUT how can i solve for v if i don't have the frequency!?
 
Last edited:
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The energy of the electron is just given by E=(1/2)*m*v^2 (no need for relativity here). Does that help?
 
Dick -
i wish i could tell you that it makes perfect sense now, but I'm still a bit confused here. When you say no relativity what exactly does that mean?
 
I mean the energy is low enough that the speed of the electron is much less than that of light. So I can use the nonrelativistic formula KE=(1/2)*m*v^2. Sorry to hear you are still confused, but why not just set 7eV equal to (1/2)*m*v^2 to find v?
 
Dick said:
Sorry to hear you are still confused, but why not just set 7eV equal to (1/2)*m*v^2 to find v?
well...i guess because i don't understand how the work function can just be set to equal the kinetic energy. how is it that the hf can just be dropped from the photoelectric equation? I sure do wish my teacher would have spent some more time on this stuff - it seems like he just left out half the info we need to complete this assignment.
 
Ok, i got the right answer but i only understand about 90% of what i did to get it. According the Photo. effect:
h*f - W = KE ...so then h*f - W = (1/2)mv^2
I guess my only question is where did the h and f disappear to?
 
Why do you think this is a photoelectric effect problem? There is no 'work function'. It's just a de Broglie wavelength problem.
 
Dart82 said:
Ok, i got the right answer but i only understand about 90% of what i did to get it. According the Photo. effect:
h*f - W = KE ...so then h*f - W = (1/2)mv^2
I guess my only question is where did the h and f disappear to?

There's no h*f in the problem either.
 
ok i see what you are saying. i guess because the only other place i have seen the eV is in the photoelectric effect problems. i have read my notes and the section in my book concerning the de Broglie Wavelength (which there were no examples problems given). consequently, i am having a tough time figuring out how to work them. The way i understand it P=mv, where v is the speed. i know KE = (1/2)mv^2. So in this instance KE = 7eV?
 
  • #10
Yes. In this case eV is just a unit of energy. I thought you were going to take a break.
 
  • #11
yes i am right now...
 
  • #12
Me too...
 

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