How to Calculate the de Broglie Wavelength of a 5.0 eV Electron?

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Homework Help Overview

The discussion revolves around calculating the de Broglie wavelength of electrons, specifically focusing on a 5.0 eV electron and another scenario involving an electron accelerating through a potential difference of 415 V. Participants are exploring the relationship between energy, momentum, and wavelength in quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the de Broglie wavelength formula and the kinetic energy relationship to find momentum. There are attempts to calculate the wavelength using given energy values, and questions arise regarding the conversion of energy units from eV to Joules.

Discussion Status

Some participants have identified errors in their calculations, particularly regarding unit conversions and the application of formulas. Others have provided guidance on correcting these issues, leading to a more productive exploration of the topic.

Contextual Notes

There is mention of confusion regarding the definition of electron-volts and how to properly convert energy values for calculations. Participants express uncertainty about the implications of potential differences in relation to energy calculations.

StudentofPhysics
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1. What is the wavelength of a 5.0 eV photon?
What is the de Broglie wavelength of a 5.0 eV electron?




2.E = hc/lambda
lambda = h/momentum




3. I know the first one simply 248 nm for the wavelngth.

I don't know how to find the de Broglie though since I don't know what the momentum of the electron is.
 
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Try finding it form:
E=\frac{p^2}{2m}
 
ok i tried it with that formula this way:

5 eV = p^2 / (9.11 x 10^-31kg)
p= 6.75 x 10^-17

this gave me a wavelength of 9.82 x 10^-18 m and wasn't correct...


I'm still doing something wrong
 
I'm having the same problem with this question:
An electron, starting from rest, accelerates through a potential difference of 415 V. What is the final de Broglie wavelength of the electron, assuming that its final speed is much less than the speed of light?

Applying that formula i get 3.41e-20

For both of these questions I figured maybe it was in nm, so i switched to meters by adding ^-9 and they were still wrong...
 
StudentofPhysics said:
ok i tried it with that formula this way:

5 eV = p^2 / (9.11 x 10^-31kg)
p= 6.75 x 10^-17

this gave me a wavelength of 9.82 x 10^-18 m and wasn't correct...I'm still doing something wrong

You probably didn't converted energy from eV in Joules. And the formula is:

E=\frac{p^2}{2m_{e}}

(2 is missing in yours). I got the result \lambda=5.48\cdot{10^{-10}}m.
 
Last edited:
the 2 and converting to joules were the problems.

Much appreciated, I've got it now.
 
what would i do for the problem with E=415V since I can't just convert that into Joules?
 
The potential difference is 415v. This is not an energy. Recall the definition of the electron-volt...
 
It would be very useful if you studied theory once again before trying to solve any more problems, becoase if you have problems on this level it means that you haven't quite got the grasp of meaning of things and you will not be able to make any progress.
 
  • #10
thank you for the tips, I figured it out on reviewing the theory. Misunderstood the 415V, its been awhile since I worked with them:rolleyes:
 

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