Find derivative of floor function using limit definition of derivative?

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Homework Help Overview

The problem involves finding the derivative of the function f(x) = 0.39 + 0.24*floor(x-1) using the limit definition of a derivative. Participants are exploring the implications of the floor function's discontinuities on differentiability.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the limit definition of the derivative and the challenges posed by the floor function. There is a consideration of whether the function is differentiable given its discontinuities, and questions arise about defining piecewise functions and the implications of continuity on differentiability.

Discussion Status

The discussion is active, with participants questioning the differentiability of the function due to its discontinuities. Some suggest examining restrictions on the domain to identify intervals where the function may be continuous. There is no explicit consensus, but several productive lines of inquiry are being explored.

Contextual Notes

Participants note that the function has infinitely many step discontinuities, particularly at integer values, which affects its differentiability. The discussion includes the need to consider non-integer values for analysis.

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Homework Statement



I have been asked to find the derivative of f(x) = 0.39 + 0.24*floor(x-1) using the limit definition of a derivative. Is this possible?

Homework Equations





The Attempt at a Solution



The limit as h approaches zero of 0.24(floor(x+h-1)-floor(x-1))/h is as far as I have got. It seems the two floor functions will cancel out when substituting in 0 for h, but I'm stuck on how to get rid of the h in the denominator.
 
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You can't substitute 0 in for h in the numerator if h is in the denominator.

Can you define a piecewise function for floor(a+b)?
 
Is a non-continuous function differentiable?
 
JonF said:
Is a non-continuous function differentiable?

If a function is differentiable (along an interval), it is continuous (along that interval). If it is continuous, it is not necessarily differentiable.
 
Is this function continuous?
 
JonF said:
Is this function continuous?

By definition, it has infinitely many step discontinuities.
 
So we are left with two options:
We can say that function isn’t differentiable as an answer.

Or we can guess that the author of the problem meant for us to look at restrictions of the domain. So for what values is this function discontinuous?
 
JonF said:
So we are left with two options:
We can say that function isn’t differentiable as an answer.

Or we can guess that the author of the problem meant for us to look at restrictions of the domain. So for what values is this function discontinuous?

It is discontinuous at every integer value...floor(1.9)=1, floor(2)=2, floor(2.1)=2, floor(2.9)=2, floor(3)=3, floor(3.1)=3...
 
So let fa(x) be a restriction on the domain of f(x) to (a,a+1) i.e. the continuous intervals. Can you write fa(x) without a floor function?
 
  • #10
JonF is correct! Adding to what he said... if a function is differentiable on an interval is has to be continuous there.
Hence, since the original function is not continuous our recourse for getting a derievative is restricting the domain to not include integers.
 
  • #11
Let x_0 be a non-integer. Then there exist \delta> 0 such that the interval [x_0- \delta, x_0+ \delta] contains only non-integers. If x and y are both in that interval, what is f(x)- f(y)?

And, of course, as other said the function is not differentiable at integer values.
 

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