Find Dielectric Constant from Parallel Plate Capacitor Problem

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JordanHood
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Homework Statement


A parallel plate capacitor has a capacitance of 1.5µF with air between the plates. The capacitor is connected a 12V battery and charged. The battery is then removed. When a dielectric is placed between the plates, a potential difference of 5.0V is measured across the plates. What is the dielectric constant of the material?

Homework Equations

The Attempt at a Solution


I know that Q=CV. however this is the only equation I find relevant as all the other equations I know for finding the dielectric constant involve area and distance between the plates. Can someone just help me get started with this question?
 
on Phys.org
Inserting a dielectric will increase the capacitance but charge on the the plates will be same. Can you write an equation with this information and find the new capacitance? Comparing the two capacitances, you can calculate the dielectric constant of the new capacitor.