Calculating the Effects of Removing Dielectric from Parallel Plate Capacitor

[wrthwrld]

A parallel plate capacitor of capacitance 10microfarads has the space between filled with material with
(dielectric constant k)= 4.0. The capacitor is charged to a potential difference of 2.0V . With the capacitor connected
to the battery the dielectric is removed.
1. The capacitance is F.
2. The potential difference across the capacitor is V .
3. The charge on the plates is C.
4. The energy stored in the capacitor is J.

F=C/V
\kappa= E_{}/E

I don't get what this is asking for or how to carry it out

 

[willem2]

I don't see a question. You seem to have included some weird latex codes that only produce a
large grey square while trying to write k = \frac {\epsilon} { \epsilon_0}