Find distance fallen given time of fall

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Homework Help Overview

The discussion revolves around calculating the distance an object falls when dropped, specifically focusing on a scenario where the object falls for 4.7 seconds. The subject area pertains to kinematics and equations of motion under gravity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the distance fallen using a formula but seems to misapply the variables. Some participants suggest using the correct formula for distance under constant acceleration due to gravity, questioning the use of time in the calculations.

Discussion Status

Participants are engaging in clarifying the correct formula to use and addressing formatting issues in the original post. There is a reference provided that may assist in understanding the concepts better, but no consensus has been reached on the correct approach yet.

Contextual Notes

There are indications of confusion regarding the application of time in the formula, and the original poster's formatting has been noted as problematic, which may hinder the clarity of the discussion.

Spenceriscool
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1.An object is dropped, and falls for 4.7 seconds before hitting the ground, how high is the object when it was dropped?2. D= 1/2a[t/f][v/i][t][/i]
D= 1/2a[t][/f]
[T][/f]= 2D/a

The Attempt at a Solution


D=1/29.8*4.7
D= 23 meters
 
Last edited:
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Welcome to PF!

Your post is terribly formatted. How do you expect anyone to answer?

Basically you start with d= 1/2 * g * t^2 and you know g=9.8 m/s/s and you have t=4.7 secs so just plug it in.

In your case, you need to use t^2 not t in your computation.
 
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