Find distance of focus point (conceptual)

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SUMMARY

The discussion revolves around calculating the focal lengths of a lens with two surfaces having different radii of curvature: R and 2R. The focal length for the left surface is determined using the formula f = r/2, resulting in f1 = 135 mm leading to R = 270 mm. The focal length for the right surface is calculated as f2 = 2r/2 = 135 mm, indicating that both surfaces affect the focal lengths differently. The conversation emphasizes the importance of understanding how varying curvature impacts focal lengths and encourages sketching ray diagrams for better conceptualization.

PREREQUISITES
  • Understanding of lens curvature and focal length relationships
  • Familiarity with the lens maker's formula
  • Basic knowledge of ray diagrams in optics
  • Concepts of convex and concave lenses
NEXT STEPS
  • Explore the lens maker's formula for different lens shapes
  • Learn about ray diagrams and their application in optics
  • Investigate the effects of lens curvature on focal length
  • Study the principles of optical systems in Quantum Physics
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Students studying optics, physics enthusiasts, and anyone interested in understanding lens behavior and focal length calculations.

Shinwasha
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Homework Statement


A lens has a radius of curvature of magnitude R on its left surface and a radius of curvature of magnitude 2R on its right surface. Parallel rays entering the lens from the left are focused to a point 135mm to the right of the right surface.
At what distance from the lens is the point at which parallel rays entering from the right are focused?

Homework Equations



f=r/2

The Attempt at a Solution


My first attempt was to find the R value

This gives me
f1= r/2
f2= 2r/2 = r

f1=r/2 = 135*2 = r = 270
f2=2r/2 = 135 = r

I'm lost with conceptual problems. Also last question for the year and just want to say thank you to everyone that's helped. On to Quantum Physics next semester :)
 
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You need to be familiar with the physics ... the reasoning is supposed to go like: R->2R->f so 2R->R-> f/2 or 2f or 4f or something.
If the two surfaces had the same R, then the focal length would be the same in both directions.
What do you think making the far surface less curved does to the focal length?
Is this the same as making the near surface more curved?

You can get a feel even just by sketching ray diagrams.
If you have some fat-lens formulae, you should have a play around with them.
Try expressing f1/f2 in terms of R1/R2
 

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