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The ratio of the distance of the focus and the point

  1. Feb 7, 2015 #1
    1. The problem statement: A ray of light is incident on a concave mirror. It is parallel to the principle axis and its height from principle axis is equal to the focal length of the mirror. the ratio of the distance of point B to the distance of the focus from the center of curvature is( AB is the reflected ray)
    A)2/√3 B)√3/2 C)2/3 D)1/2


    2. Answer to this problem give is: A

    3. The attempt at a solution: the ray of light is parallel to principle axis so it should pass through the focus. the point of the focus and the point of intersection of the ray and the focus are same. so i thought the answer is 1.
    Have I done anything wrong?
     

    Attached Files:

  2. jcsd
  3. Feb 7, 2015 #2

    BvU

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    What are the relevant equations for a concave mirror ?
     
  4. Feb 7, 2015 #3
    radius of curvature is twice that of focal length..
     
  5. Feb 7, 2015 #4

    BvU

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    So the drawing should not be showing an R where it is drawn now. That's confusing.
    What are A and B ?
     
  6. Feb 7, 2015 #5
    Here that's not R sorry for that .
    That's B and the ray that is reflected from the concave mirror is AB
     
  7. Feb 7, 2015 #6

    BvU

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    Good. Now re-read your first post and explain what ratio is asked for, because it's not really clear what is meant with
     
  8. Feb 10, 2015 #7
    the ratio = the distance of point b from radius of curvature / the distance from focus to radius of curvature
     
  9. Feb 10, 2015 #8

    BvU

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    Well, maybe I have to come back on my "Good" in post #6. As you describe it, B = F and the ratio is 1.

    Since the answer is given, and it's ##1/{1\over 2}\sqrt 3## I start to suspect that B is not F. Could it be that B is the x-axis coordinate of the point where the beam is reflected on the mirror ?

    [edit] oops... see bold faced.
     
    Last edited: Feb 10, 2015
  10. Feb 10, 2015 #9
    B is the point on the principle axis where the reflected ray intersects with the principle axis. A is the point where the ray touches the mirror. (sorry I forgot to mention that point).
     
  11. Feb 10, 2015 #10
    is there any relation , if the distance between the ray and principle axis is f? i mean will the ray pass through the focus if the distance between the principle axis and the ray is f, even though the ray is parallel to the axis.
     
  12. Feb 10, 2015 #11

    BvU

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    That's the idea of the thin lens / mirror rays: what comes in through the focus goes out parallel and vice versa.

    My picture so far is (for the B = F)


    mirror.jpg

    And the one I like is the ? one ...
     
  13. Feb 10, 2015 #12
    yah! but the question given is the same as ive mentioned ! i really dont know what he meant to find?
     
  14. Feb 10, 2015 #13

    BvU

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    ? / AR = 2/sqrt(3)
     
  15. Feb 10, 2015 #14
    thanks for the help!!! It does mean that i understood the question in a wrong way
     
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