Find f'(1), ∂g/∂s(1, 1), and ∂g/∂t(1,1).

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Homework Help Overview

The problem involves finding the derivative f'(1) and the partial derivatives ∂g/∂s(1, 1) and ∂g/∂t(1, 1) in the context of differentiation and partial differentiation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to differentiate components of a function F and expresses uncertainty about the correctness of their approach. They seek clarification on the next steps. Other participants suggest differentiating the components of g(s,t) and substituting values, while one participant questions the accuracy of their interpretation.

Discussion Status

Some guidance has been offered regarding the differentiation process, but there is a lack of consensus on the correctness of the original poster's approach. Multiple interpretations of the problem are being explored, with some participants expressing uncertainty about the answers.

Contextual Notes

The original poster mentions a discrepancy between their answers and the provided correct answers, indicating potential confusion or missing information in their understanding of the problem.

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Homework Statement


The problem is attached.

The correct answers are:
f'(1) = -68
∂g/∂s(1, 1) = 14
∂g/∂t(1, 1) = -136

Homework Equations


Differentiation and partial differentiation.

The Attempt at a Solution


I'm at the f'(1) part. I differentiated each component of F(2 – 3t + 2t^2, 19 – 27t + 9t^2, -4 + 3t + 2t^2) to get f'(t) = F(-3 + 4t, -27 + 18t, 3 + 4t) and then f'(1) = F(1, -9, 7). I'm not entirely certain if what I did is correct so far. If it is, what do I do next? If I omitted something important, tell me.

Any help in solving this problem would be greatly appreciated!
Thanks in advance!
 

Attachments

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Looks fine to me.

Now differentiate the components of g(s,t) first with respect to s, then with respect to t, and plug in (1, 1) just like before.
 
Wait I misread this. Something is off...
 
My answer differs from the correct answer quite a bit ;). Thanks anyways though.

If someone else knows, please help me.
 

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