Find f(z) when |z|<=1 and |f(z)|=|e^z| for |z|=1

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Homework Help Overview

The problem involves finding a function f(z) that is analytic and non-zero within the unit circle (|z|<=1), with the condition that |f(z)|=|e^z| on the boundary (|z|=1). Participants are exploring the implications of these conditions and the nature of the solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants discuss the uniqueness of the solution and whether the problem implies a single correct answer. Others express uncertainty about the simplicity of the solution, suggesting that it may require more than just stating e^z.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have suggested that the question may be worded poorly, while others are questioning the necessity of a more complex solution. There is a mix of agreement and disagreement regarding the nature of the answer.

Contextual Notes

Participants note that the question may not be straightforward and could imply a level of complexity beyond a simple solution. There is also a sense of frustration regarding the perceived simplicity of the problem in relation to its academic level.

Cosmossos
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f(z) is analytic and not equal to zero in the unit circle (|z|<=1) . we also know that |f(z)|=|e^z| for |z|=1. find f(z)

How should i approch to this question? I know that on inside the boundary it can't get the maximum nor the minimum .. but it doesn't help at all. i have no idea what to do.
 
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Does the question imply that there is a unique answer? It is obvious that the function f(z)= e^z itself satisfies all of those properties,
 
no, but I'm asked to find it, so I think i should do more than that
 
Cosmossos said:
no, but I'm asked to find it, so I think i should do more than that

Jesus dude, you kinda' antagonizing huh? I mean you got a flat tire, I say, "hey, here's one that's not flat that'll fit, use it," and you say, "oh no, that one won't work." So I say, "dude, it's the same diameter, same lugs, and best of all, it's ain't flat." Then you say, . . . ok, I'll stop being anoying.
 
The question is written in a way that implies that the answer is not just ez. But maybe the question is just worded badly.
 
jackmell said:
Jesus dude, you kinda' antagonizing huh? I mean you got a flat tire, I say, "hey, here's one that's not flat that'll fit, use it," and you say, "oh no, that one won't work." So I say, "dude, it's the same diameter, same lugs, and best of all, it's ain't flat." Then you say, . . . ok, I'll stop being anoying.

Huh? the simple answer isn't going to work here and it is like giving the trivial solution for a set of equations . This question isn't a stupid college question but some levels above that and needed a little bit more then just stating the answer . jackmell , next time, think before you shoot...

By the way, this isn't the complete answer ... so my friend, I'm glad I didn't took you tire...

And for the one who actually try to answer my question, thank you very much and I didn't meant to insult you in any way.
 
BruceW said:
The question is written in a way that implies that the answer is not just ez. But maybe the question is just worded badly.

You are correct
 
It's a teachable moment. Sometimes in math, the obvious solution is in fact the answer. Don't try and make it more complicated than it is. Final exam, you ask me that question, I'm going with e^x. Bingo-bango, wait a while so I'm not the first one to leave the class then I'm outta there.
 
jackmell said:
It's a teachable moment. Sometimes in math, the obvious solution is in fact the answer. Don't try and make it more complicated than it is. Final exam, you ask me that question, I'm going with e^x. Bingo-bango, wait a while so I'm not the first one to leave the class then I'm outta there.

In that case you got 5 out of 20. enjoy
 
  • #10
I don't think there is a single teacher teaching Complex Analysis in the entire world that would disagree with me. Well, maybe not the smart-elic stuf. Mostly just playing around.
 
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  • #11
Cosmossos said:
By the way, this isn't the complete answer ...

You sound like you have some idea of what the actual answer is..?
If I had to guess, I would say ez was a correct answer, despite the strangely-worded question.
 
  • #12
Cosmossos said:
Huh? the simple answer isn't going to work here and it is like giving the trivial solution for a set of equations .
Why not? That was why I asked "Does the question imply that there is a unique answer?" The question said " find f(z)" which seems to me to imply that there is a unique solution- in which case it would have to be e^z.

This question isn't a stupid college question but some levels above that and needed a little bit more then just stating the answer . jackmell , next time, think before you shoot...

By the way, this isn't the complete answer ... so my friend, I'm glad I didn't took you tire...

And for the one who actually try to answer my question, thank you very much and I didn't meant to insult you in any way.
 
  • #13
There is another possibility for f(z) that I can think of.
 
  • #14
BruceW said:
There is another possibility for f(z) that I can think of.

Do you mind sharing?
 
  • #15
Does it matter? Its another obvious one. And you said "but I'm asked to find it, so I think i should do more than that ... the simple answer isn't going to work here and it is like giving the trivial solution for a set of equations ... By the way, this isn't the complete answer " So I'm guessing you've been told that its not just an easy answer?
 
  • #16
BruceW said:
Does it matter? Its another obvious one. And you said "but I'm asked to find it, so I think i should do more than that ... the simple answer isn't going to work here and it is like giving the trivial solution for a set of equations ... By the way, this isn't the complete answer " So I'm guessing you've been told that its not just an easy answer?

come on ... The level of the course is more than that. believe me , I KNOW.
No one would give us this question if that was the answer
 
  • #17
If it is not an easy answer, then I can't for the life of me think what the answer is. Sorry I haven't really been able to help
 
  • #18
Thank you everyone for try to help me!
 

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