Find First Place Where F <= 0 in O(log n) Time

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SUMMARY

The discussion centers on finding the first index where a strictly decreasing function F: ℕ → ℤ is less than or equal to zero in O(log n) time. The problem states that F(0) > 0, and participants explore the feasibility of using binary search after determining an upper bound for i. The confusion arises from the lack of a finite input size, leading to questions about how to define n in this context. Ultimately, the key takeaway is that establishing a valid range for i is essential for applying binary search effectively.

PREREQUISITES
  • Understanding of strictly decreasing functions
  • Knowledge of binary search algorithms
  • Familiarity with Big O notation and time complexity
  • Basic concepts of mathematical functions and their properties
NEXT STEPS
  • Study the implementation of binary search in unbounded domains
  • Learn about the properties of strictly decreasing functions
  • Explore how to define bounds for infinite sequences in algorithm design
  • Investigate the implications of Big O notation in non-finite contexts
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Mathematicians, computer scientists, algorithm developers, and students tackling advanced algorithmic problems related to function evaluation and time complexity.

Jcampuzano2
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Homework Statement



Consider a strictly decreasing function F: ℕ → ℤ. We want to find the "first place where f is at or below the horizontal axis." Assume we can compute ƒ(i) for any input i in constant time. Clearly, we can solve the problem in O(n) time by evaluating ƒ(1), ƒ(2), ƒ(3),... until we see a non-positive number. Give an O(log n) algorithm.

Homework Equations


The only given is that ƒ(0) > 0.

The Attempt at a Solution



I'm a little confused on this problem. I don't have a finite input size, so I can't just access the last element in an array like I'm used to on algorithm problems. My only guess so far is that I could could pick a random number and test whether it is less than 0. If it is, then I can say that that can be considered the last element in an set, and perform a binary search to find the first place where the value is less than 0, but what if it takes greater than O(log n) time just to find this initial value?

So for example I test say f(100). if that is less than 0, then my input set can be say 0, 1, ... 100. and do a binary search using this as input. Would this be the correct way to go about this? It's literally the only way I can think of.
 
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I'm a bit confused. If an algorithm can be said to be O(n), it means that n is defined, that there is a number of input data. If you indeed let i not be constrained, then saying that an algorithm is O(n) doesn't make sense to me.

Could it be that n is constrained by the largest ℕ that can be expressd depending on the data type of i?
 
DrClaude said:
I'm a bit confused. If an algorithm can be said to be O(n), it means that n is defined, that there is a number of input data. If you indeed let i not be constrained, then saying that an algorithm is O(n) doesn't make sense to me.

Could it be that n is constrained by the largest ℕ that can be expressd depending on the data type of i?

That's part of where my confusion comes from as well. This problem isn't given with any data types in its context. I might just have to ask for more info on this one. The only part of the problem I left out because it was explained in the problem is the following sentenct:

We want to find

n = min{ i ∈ ℕ : ƒ(i) ≤ 0} .

But that was explained in the next sentence "first place where f is at or below the horizontal axis." Maybe that helps, but I don't think it does. Correct me if I'm mistaken.
 
Jcampuzano2 said:
Maybe that helps, but I don't think it does.
I'm still as confused. And the more I think about it, the more I'm convinced that the question only makes sense if the value of i is bounded.
 

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