Find Generators of Lorentz Group: Jackson's List & K Matrix

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SUMMARY

The discussion focuses on identifying the generators of the Lorentz group, specifically referencing Jackson's list. The generator of a boost along the x-axis is represented by a specific matrix format. The main inquiry revolves around the classification of this matrix as a covariant, contravariant, or mixed tensor, with the user questioning the appropriate notation for the generator. The conclusion drawn is that the generator, being the derivative of a transformation, is indeed a mixed tensor.

PREREQUISITES
  • Understanding of Lorentz transformations
  • Familiarity with tensor notation and types (covariant, contravariant, mixed)
  • Knowledge of matrix representation in physics
  • Basic concepts of group theory in the context of physics
NEXT STEPS
  • Study the properties of Lorentz transformations in detail
  • Learn about tensor calculus and its applications in physics
  • Research the mathematical structure of the Lorentz group
  • Explore Jackson's "Classical Electrodynamics" for further examples of generators
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Physicists, mathematicians, and students studying theoretical physics, particularly those interested in group theory and tensor analysis in the context of relativity.

eoghan
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Hi!
I'm trying to find the generators of the Lorentz group. Jackson lists them all, for example, the generator of a boost along x is:
[tex] K=\left( \begin{array}{c}<br /> 0\;1\;0\;0 \\<br /> 1\;0\;0\;0 \\<br /> 0\;0\;0\;0 \\<br /> 0\;0\;0\;0 <br /> \end{array} \right)[/tex]

Now, what I don't understand is: this matrix is a covariant, contravariant, or mixed tensor? I mean, should I write
[tex]K_{\mu\nu}\:\:,\:\:K_{\mu}\;^{\nu}\:\:,\:\:K^{\mu \nu}...[/tex] or what else?
 
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A Lorentz transformation takes a vector to a vector. A generator is the derivative of that with respect to a parameter in the transformation. Wouldn't that make it a mixed tensor? Like [itex]x'^\mu = T_\nu^\mu x^\nu[/itex].
 
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