Find image distance multiple optics.

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SUMMARY

The discussion focuses on calculating image distances using a concave mirror and a converging lens. The concave mirror has a focal length of 10.0 cm, while the converging lens has a focal length of 32.0 cm, positioned 85.0 cm to the right of the candle. The first image distance calculated is 51.3 cm, and the second image is formed by light reflecting off the mirror before passing through the lens. The object distance for the mirror is at the center of curvature, leading to an inverted image that serves as the object for the lens.

PREREQUISITES
  • Understanding of optics principles, specifically image formation by mirrors and lenses.
  • Familiarity with the lens formula: 1/s + 1/s' = 1/f.
  • Knowledge of focal lengths and their significance in image distance calculations.
  • Basic skills in geometric optics and ray diagrams.
NEXT STEPS
  • Explore the derivation and applications of the lens formula in various optical systems.
  • Study the behavior of light in multiple lens systems, focusing on image formation and distance calculations.
  • Learn about the principles of ray tracing for concave mirrors and converging lenses.
  • Investigate the effects of changing object distances on image characteristics in optical setups.
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of image formation using mirrors and lenses.

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Homework Statement


As shown in the figure View Figure the candle is at the center of curvature of the concave mirror, whose focal length is 10.0 {\rm cm}. The converging lens has a focal length of 32.0 {\rm cm} and is 85.0 {\rm cm} to the right of the candle. The candle is viewed looking through the lens from the right. The lens forms two images of the candle. The first is formed by light passing directly through the lens. The second image is formed from the light that goes from the candle to the mirror, is reflected, and then passes through the lens.

http://session.masteringphysics.com/problemAsset/1043040/4/YF-34-094.jpg

Homework Equations


1/s+1/s'=1/f

The Attempt at a Solution


I have already found the first image to be a distance of 51.3 cm I am now looking for the second image.
Trying to figure out what I put for the object distance to the concave mirror or do I not worry about it.
 
Last edited:
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Since the object is at the center of curvature, you know that the image formed from the mirror will be at the same center of curvature, only the image will be inverted. Now, use this image as the object for the lens -- you should find that the image distances are the same for both situations. However, in one case the object will be inverted with respect to the original object, and the other will be upright.
 

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