# Find image distance multiple optics.

• viperassasin
In summary, the candle is placed at the center of curvature of a concave mirror with a focal length of 10.0 cm. A converging lens with a focal length of 32.0 cm is placed 85.0 cm to the right of the candle. Looking through the lens from the right, two images of the candle are formed - one through direct light and the other through light that is reflected by the mirror. By using the equation 1/s + 1/s' = 1/f, the image distance for the first image is found to be 51.3 cm. To find the image distance for the second image, the first image is used as the object for the lens. The distances for both images
viperassasin

## Homework Statement

As shown in the figure View Figure the candle is at the center of curvature of the concave mirror, whose focal length is 10.0 {\rm cm}. The converging lens has a focal length of 32.0 {\rm cm} and is 85.0 {\rm cm} to the right of the candle. The candle is viewed looking through the lens from the right. The lens forms two images of the candle. The first is formed by light passing directly through the lens. The second image is formed from the light that goes from the candle to the mirror, is reflected, and then passes through the lens.

http://session.masteringphysics.com/problemAsset/1043040/4/YF-34-094.jpg

1/s+1/s'=1/f

## The Attempt at a Solution

I have already found the first image to be a distance of 51.3 cm I am now looking for the second image.
Trying to figure out what I put for the object distance to the concave mirror or do I not worry about it.

Last edited:
Since the object is at the center of curvature, you know that the image formed from the mirror will be at the same center of curvature, only the image will be inverted. Now, use this image as the object for the lens -- you should find that the image distances are the same for both situations. However, in one case the object will be inverted with respect to the original object, and the other will be upright.

I would approach this problem by using the equation 1/s + 1/s' = 1/f to determine the image distance for the second image formed by the light that goes through the mirror. In this equation, s represents the object distance and s' represents the image distance. Since the candle is located at the center of curvature of the concave mirror, the object distance can be assumed to be infinity. Therefore, the equation becomes 1/∞ + 1/s' = 1/10.0 cm. Simplifying this, we get 1/s' = 1/10.0 cm, which means that the image distance for the second image is also 10.0 cm. This means that the second image is formed at the same location as the first image.

## 1. How do I calculate the image distance using multiple optics?

To calculate the image distance using multiple optics, you will need to use the thin lens equation. This equation states that 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the object distance, and di is the image distance. You will need to apply this equation for each lens in the system and then sum up the individual image distances to get the total image distance.

## 2. How do I determine the focal length of a lens in a multiple optics system?

To determine the focal length of a lens in a multiple optics system, you can use the thin lens equation mentioned above. Rearrange the equation to solve for f, and then substitute the known values for do and di for that particular lens. Alternatively, you can also use experimental methods such as the lensmaker's formula or the lens displacement method to determine the focal length of a lens.

## 3. How does the number of lenses in a system affect the overall image distance?

The number of lenses in a system can affect the overall image distance in several ways. If the lenses are arranged in a way that the image of one lens is the object for the next lens, the image distance will be the sum of the individual image distances. However, if the lenses are placed close together, they can act as a single lens with a combined focal length, which can change the overall image distance.

## 4. What is the difference between image distance and object distance?

Image distance and object distance are two important parameters in optics. Image distance refers to the distance from the lens to the location of the image formed, while object distance refers to the distance from the lens to the object being observed. These two distances are related by the thin lens equation and play a crucial role in determining the characteristics of the image formed by a lens.

## 5. Can the image distance be negative in a multiple optics system?

Yes, the image distance can be negative in a multiple optics system. This can happen when the object is placed within the focal length of a converging lens, resulting in a virtual image being formed on the same side as the object. In this case, the image distance will be negative, indicating that the image is a virtual image. However, if the object is placed outside the focal length of the lens, the image distance will be positive, indicating a real image being formed on the opposite side of the lens.

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