Find Inductance: Lab Experiment & Graph Analysis

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SUMMARY

The discussion focuses on calculating the inductance (L) in a resistor-inductor (RL) series circuit using a triangular waveform input from a generator. The key equation utilized is V = L (dI/dt), which can be rearranged to L = R (Δt/ΔV) to find the inductance based on the voltage across the inductor (VL) and the known resistance (R). Participants emphasize the importance of understanding the graph's characteristics to accurately apply the equations for inductance calculation.

PREREQUISITES
  • Understanding of RL circuit theory
  • Familiarity with the relationship between voltage, current, and inductance
  • Basic knowledge of differential calculus
  • Experience with waveform analysis
NEXT STEPS
  • Study the application of the formula L = R (Δt/ΔV) in various circuit scenarios
  • Learn how to analyze triangular waveforms in electrical circuits
  • Explore the effects of different resistance values on inductance calculations
  • Investigate advanced inductance measurement techniques using oscilloscopes
USEFUL FOR

Electrical engineering students, lab technicians, and educators involved in circuit analysis and inductance measurement will benefit from this discussion.

mathman44
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Homework Statement



Find the inductance L. This is for a lab experiment. For a resistor-inductor series circuit, I have a graph of a triangular input waveform from a generator and the voltage across the inductance, VL, as a function of time. I also have the value of the resistance R.

The Attempt at a Solution



Well, given this information, I need to find the value of L. I've looked over the equations which seem most relevant but I can't find a suitable one. What am I overlooking?
 
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Without knowing how your graph looks or any other specifics of your problem, it's a bit hard for me to help, I don't know about anyone else. Here's what I can tell you:

You know that

[tex]V = L \frac{dI}{dt} = L \frac{\Delta I}{\Delta t}[/tex]

which will give you the voltage drop across the inductor.
 
Yeah that's what we did, we rearranged the equation to be L=RV(dt/dv)
 

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