But is it the same for AC circuits?

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Homework Help Overview

The discussion revolves around a series LCR circuit where the voltages across the resistance, capacitance, and inductance are initially equal. The problem explores the scenario when the capacitance is short-circuited and seeks to determine the new voltage across the inductance.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of short-circuiting the capacitance and how it transforms the circuit into an LR circuit. There are questions about how to recalculate the voltages across the components and the relationships between them.

Discussion Status

Participants are actively engaging with the problem, raising questions about the equations needed and the conditions under which the voltages across the components are equal. Some guidance has been offered regarding the application of relevant equations, but there is no explicit consensus on the approach to take.

Contextual Notes

There is an ongoing discussion about the definitions of voltage in terms of RMS versus maximum values, and the need for clarity in the problem statement regarding these terms. Participants also note the importance of resonance conditions in the circuit.

harambe
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Homework Statement


For a series LCR circuit,the voltage across the resistance,capacitance and inductance is 10V each.If the capacitance is short circuited,the voltage across the inductance will be

(a)10V
(b)10/√2V
(c) 10/3v
(d)20V

Homework Equations



Potential difference across Inductance=I/XL
I=V/(R^2+(XL)^2)

The Attempt at a Solution



Okay so initially the capacitance,reactance as well as the inductance were equal
VR=VL=VC=10[/B]

Now VC=0 so It will act as a LR circuit whose voltage is given by

V=(VR)^2+(VL)^2

So how should I Calculate the new VR and VL?I think they will change from the first case because our circuit has changed but I am not too sure.If I apply the analogy of DC circuits then only current will change and reactance and inductance will remain same so I can calculate the Current.
 
Last edited:
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harambe said:
So how should I calculate the V,VR and VL here?
Good question. But it doesn't count as an attempt at solution, so we can't help.

The general idea at PF is: you apply the relevant equations (where are yours?) to the known variables in order to derive the unknowns.

By way of (not really deserved :rolleyes:) hint: what else do you know of the voltage over C, L and R ?
 
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(VR)^2+({VL)^2+(VC)^2}=(V)^2

From here the Voltage comes out to be 10V(Forgot to use this srsly)
 
How many equations with how many unknowns do you have now ?
My guess is you'll need something more... when is it that C and L have the same V ?
 
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harambe said:
V=(VR)^2+(VL)^2
Something not quite right there ...
 
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C and L have the same V at resonance

V={(VR)^+{(VL)^2-(VC)^2}} (Misplayed the negative sign)
 
*I found the Vrms to be 10V (Can this be maximum voltage instead of Vrms) *

Now I proceeded like this

R=XL

therefore since current will be same since they are in series

(I rms)= (V)^2/{(R)^2+(XL)^2)

(I rms)= 5√2/XL (R=XL)

So I calculated the VL=I rms x XL =5√2
I calculated after your hint but I am confused about the star statement

 
harambe said:
at resonance
Right. So the circuit is at resonance and you know XL = R. Bingo: post #7 is OK :smile:.

Whether V is rms or amplitude does not matter for the answer -- as long as problem statement and answer refer to the same.

(But it would have been nicer if the exercise had indicated one of the two)
 
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Yea. Thanks for the help
 
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You're welcome.
 

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