Find Initial Speed for Olympic Basketball Player to Score

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SUMMARY

The discussion focuses on calculating the initial speed required for an Olympic basketball player to successfully score by shooting a basketball towards a basket positioned 5.80 meters away and 3.05 meters high. The ball is released from a height of 1.94 meters at an angle of 64.0 degrees above the horizontal. The relevant kinematic equations used include Vx^2 = Vox^2 + 2ax (x-xo) and Vy^2 = Voy^2 + 2ax (y-yo). The solution involves breaking down the initial velocity into horizontal (Vox) and vertical (Voy) components and applying parametric equations to determine the projectile's trajectory.

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Homework Statement


An Olympic basketball player shoots towards a basket that is 5.80 m horizontally from her and 3.05 m above the floor. The ball leaves her hand 1.94 m above the floor at an angle of 64.0 degree above the horizontal.
What initial speed should she give the ball so that it reaches the basket and hopefully scores?

Homework Equations


Vx^2 = Vox^2 + 2ax (x-xo)
Vy^2 = Voy^2 + 2ax (y-yo)



The Attempt at a Solution


Im not even sure if these are the right equations to use, but in this case, I would want to find Vox and Voy? With that, can I find the magnitude of the initial speed. How do I incorporate the 64 degree angle.

Any help is appreciated, thanks
 
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The motion in the horizontal direction is not accelerated in any way and hence the velocity in the horizontal direction is constant. Use the the components method then to express the initial velocity of the ball horizontally and vertically. Knowing the distances, use the kinematics equations to derive a set of parametric equation for the projectile trajectory in the absence of air friction.
 

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