Find Initial Velocity: Time = 2.58s, Distance = 9.87m

Click For Summary
SUMMARY

The discussion focuses on calculating the initial velocity of a ball given a time of 2.58 seconds and a distance of 9.87 meters. The relevant equation is x = x0 + v0t + ½at², where acceleration (a) is critical for determining initial velocity (v0). Participants clarify that if the ball is falling, the acceleration due to gravity is approximately 9.81 m/s². The conversation emphasizes the need to establish whether the ball is subject to gravitational acceleration to solve for initial velocity accurately.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with the concept of initial velocity
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in vertical motion
  • Learn how to derive initial velocity from distance and time using the equation x = x0 + v0t + ½at²
  • Explore the effects of acceleration on projectile motion
  • Investigate real-world examples of objects in free fall to understand practical applications of these concepts
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion under the influence of gravity.

Jillypilly9
Messages
1
Reaction score
0

Homework Statement


Find the initial velocity of a ball with the time=2.58 seconds and distance of 9.87 meters

Homework Equations


vi=v-at


The Attempt at a Solution


I don't understand how to find the acceleration with just time and distance is it just 9.8 m^3/second?
 
Physics news on Phys.org
I can't gather from the problem that the ball experiences any acceleration. The really basic equation that comes to mind is: x=xo+vot+½at2. Give that a try.

In the case that the ball is falling vertically, a=10ms-² instead of zero (9.81ms-² if you wanted to be more precise).
 
Welcome to Physics Forums :smile:
Jillypilly9 said:

Homework Statement


Find the initial velocity of a ball with the time=2.58 seconds and distance of 9.87 meters

Homework Equations


vi=v-at

The Attempt at a Solution


I don't understand how to find the acceleration with just time and distance is it just 9.8 m^3/second?
How exactly is the problem worded? Is there any indication that the ball is falling?
 

Similar threads

Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K