How do you find the initial velocity of a projectile given angle/distance?

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Homework Help Overview

The discussion revolves around finding the initial velocity of a projectile given its launch angle and horizontal distance traveled. The context involves a physics problem where a ball is thrown from a height with a specific angle below the horizontal.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss resolving the problem into vertical and horizontal components and express uncertainty about how to incorporate the angle into their calculations. There are attempts to identify relevant variables and equations that relate the horizontal and vertical motions.

Discussion Status

The conversation includes attempts to clarify the problem setup and explore different approaches to find the initial velocity. Some participants have expressed that they have made progress in understanding the problem, while others continue to seek guidance on how to connect the given information effectively.

Contextual Notes

Participants note the constraints of the problem, including the height from which the ball is thrown and the distance it lands from the building. There is also mention of the need to use specific equations related to constant acceleration.

iamcgettigan
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Homework Statement
I am in 10th grade physics. The question is: A person standing on top of a 30.0 m high building throws a ball with an angle of 20.0° below horizontal. If the ball lands 29.3 m away from the building, what is the initial velocity of the ball? I know the answer is 16m/s, however I am unsure of how to arrive at this answer.
Relevant Equations
s=ut+½at^2
I tried resolving the information given into vertical and horizontal components. I then tried to find time, as this is how I would find the initial velocity. However, I am unsure of how to use the angle in this problem to help solve it. I am also unsure of how to find the initial velocity only given angle and distances. Any help would be greatly appreciated!
 
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iamcgettigan said:
Homework Statement:: I am in 10th grade physics. The question is: A person standing on top of a 30.0 m high building throws a ball with an angle of 20.0° below horizontal. If the ball lands 29.3 m away from the building, what is the initial velocity of the ball? I know the answer is 16m/s, however I am unsure of how to arrive at this answer.
Relevant Equations:: s=ut+½at^2

I tried resolving the information given into vertical and horizontal components. I then tried to find time, as this is how I would find the initial velocity. However, I am unsure of how to use the angle in this problem to help solve it. I am also unsure of how to find the initial velocity only given angle and distances. Any help would be greatly appreciated!
Please post your work as far as you get (and please, not as an image).

In the standard form of constant acceleration equations (SUVAT) there are five variables. Each equation relates four of them, so five equations for vertical motion. Horizontal is somewhat simpler.

The trick is to identify those variables which are of interest and choose your equations accordingly. Any variable you are given in the question and any variable you are asked to find is of interest. A variable which connects the horizontal and vertical motions (there is one here) is also relevant.
 
haruspex said:
Please post your work as far as you get (and please, not as an image).

In the standard form of constant acceleration equations (SUVAT) there are five variables. Each equation relates four of them, so five equations for vertical motion. Horizontal is somewhat simpler.

The trick is to identify those variables which are of interest and choose your equations accordingly. Any variable you are given in the question and any variable you are asked to find is of interest. A variable which connects the horizontal and vertical motions (there is one here) is also relevant.

Thank you for your response. I am sorry to have somewhat wasted your time as I have figured it out. Thanks again.
 
iamcgettigan said:
Thank you for your response. I am sorry to have somewhat wasted your time as I have figured it out. Thanks again.
That's fine - glad you got there by your own efforts.
 

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