Find Invariant Lines of Matrix Transformation y=mx+c

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SUMMARY

The discussion focuses on finding invariant lines of the transformation represented by the matrix \(\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\). The transformation swaps the x and y coordinates, leading to the equation X = m(mx + c) for invariant lines in the form y = mx + c. Participants clarify that the goal is to determine lines where the x-value remains unchanged after the transformation, resulting in the derived relationship Y = M(mx + c) + C. This process is essential for understanding how linear transformations affect geometric representations.

PREREQUISITES
  • Understanding of linear transformations and matrices
  • Familiarity with the concept of invariant lines
  • Knowledge of the equation of a line in the form y = mx + c
  • Basic algebraic manipulation skills
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  • Study the properties of linear transformations in vector spaces
  • Learn about eigenvalues and eigenvectors in relation to invariant lines
  • Explore matrix multiplication and its geometric interpretations
  • Investigate other forms of transformations and their effects on lines
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Students in linear algebra, mathematicians exploring geometric transformations, and educators teaching concepts of matrix operations and invariant lines.

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Homework Statement



find in the form y= mx+c, the invariant lines of the tranformation with matrix

[itex] \left(<br /> \begin{array}{cc}<br /> 0 & 1 \\<br /> 1 & 0<br /> \end{array}<br /> \right)[/itex]

[itex] <br /> \left(<br /> \begin{array}{cc}<br /> 0 & 1 \\<br /> 1 & 0<br /> \end{array}<br /> \right)\left(<br /> \begin{array}{c}<br /> x \\<br /> \text{mx}+c<br /> \end{array}<br /> \right)=\left(<br /> \begin{array}{c}<br /> \text{mx}+c \\<br /> x<br /> \end{array}<br /> \right)<br /> [/itex]

[itex]\Rightarrow x = m(mx+c)+c[/itex] Why?

I just don't understand how that is implied in the first place and I don't have a method of working out invariant lines in the form mx or mx+c!
 
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Because you want a line whose x value will remain the same after undergoing the transformation.


So when you multiply the matrix by (x,y) you get (y,x). You then want your line to have the the x value of the 'old y value'

and if Y=MX+C

X= mx+c

so Y=M(mx+c) + C

(I used capital letters to explain it better even though, the capitals are the same as the common ones)
 

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