Find k & m for Perpendicular Line to U, W & V Plane

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SUMMARY

The discussion focuses on determining the values of k and m for the line defined by the equation x+1/k = y-2/m = z+3/1 to be perpendicular to the plane formed by the points U(1,3,8), W(0,1,1), and V(4,2,0). The line's direction vector is , while the normal vector to the plane is calculated as <9, -29, 7> using the cross product of vectors UW and WV. For the line to be perpendicular to the plane, the direction vector must be parallel to the normal vector, leading to the conclusion that k and m must satisfy the proportional relationship k/9 = m/-29 = 1/7.

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shawen
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find the values of k and m so that the line x+1/k = y-2/m = z+3/1 is perpendicilar to the plane through the points U(1,3,8) , W(0,1,1) , and v(4,2,0).PLEASE HELP ME
THANKS a lot :)
 
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shawen said:
find the values of k and m so that the line x+1/k = y-2/m = z+3/1 is perpendicilar to the plane through the points U(1,3,8) , W(0,1,1) , and v(4,2,0).PLEASE HELP ME
THANKS a lot :)

The equation of the line shows that the line is parallel to the vector $<k, m,1>$. A normal to the plane is

$\vec{UW} \times \vec{WV} =\, <-1,-2,-7> \times <4,1,-1> =\, <9,-29,7>$.

For the line to be perpendicular to the plane, the normal $<9,-29,7>$ must be parallel to $<k, m, 1>$. So what does that tell you about $k$ and $m$?
 

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