MHB Find k & m for Perpendicular Line to U, W & V Plane

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To find the values of k and m for the line x+1/k = y-2/m = z+3/1 to be perpendicular to the plane defined by points U(1,3,8), W(0,1,1), and V(4,2,0), the line's direction vector <k, m, 1> must be parallel to the plane's normal vector <9, -29, 7>. This means that the ratios of the components must be equal, leading to the equations k/9 = m/(-29) = 1/7. Solving these ratios provides the necessary values for k and m. The discussion emphasizes the relationship between the line's direction and the plane's normal for establishing perpendicularity.
shawen
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find the values of k and m so that the line x+1/k = y-2/m = z+3/1 is perpendicilar to the plane through the points U(1,3,8) , W(0,1,1) , and v(4,2,0).PLEASE HELP ME
THANKS ALOT :)
 
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shawen said:
find the values of k and m so that the line x+1/k = y-2/m = z+3/1 is perpendicilar to the plane through the points U(1,3,8) , W(0,1,1) , and v(4,2,0).PLEASE HELP ME
THANKS ALOT :)

The equation of the line shows that the line is parallel to the vector $<k, m,1>$. A normal to the plane is

$\vec{UW} \times \vec{WV} =\, <-1,-2,-7> \times <4,1,-1> =\, <9,-29,7>$.

For the line to be perpendicular to the plane, the normal $<9,-29,7>$ must be parallel to $<k, m, 1>$. So what does that tell you about $k$ and $m$?
 

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