Find length of a string, given a strange condition

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SUMMARY

The discussion focuses on determining the unstretched length of a spring when an apple weighing 1.11 N is attached, causing it to oscillate in simple harmonic motion (SHM). The spring has a force constant of 1.53 N/m. The relationship between the frequencies of the spring's oscillation and the pendulum's swing is established, with the pendulum's frequency being half that of the spring. The correct approach involves using Hooke's Law and the formulas for SHM and pendulum motion to relate the stretched and unstretched lengths of the spring.

PREREQUISITES
  • Understanding of Hooke's Law (F = -kx)
  • Knowledge of simple harmonic motion (SHM) equations
  • Familiarity with pendulum motion formulas (T = 2π√(L/g))
  • Basic concepts of frequency and period relationships
NEXT STEPS
  • Review the derivation of the frequency formula for a spring (f = 1/2π√(k/m))
  • Study the relationship between frequency and period in oscillatory systems
  • Explore examples of Hooke's Law applications in real-world scenarios
  • Investigate energy conservation principles in spring-mass systems
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of spring-mass systems and pendulum motion in classical mechanics.

wayfarer
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Homework Statement


An apple weighs 1.11 N. When you hang it from the end of a long spring of force constant 1.53 N/m and negligible mass, it bounces up and down in SHM. If you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (Because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.)
What is the unstretched length of the spring (i.e., without the apple attached)?

Homework Equations


I think these are the relevant ones:
For a normal spring, f = 1/2*pi ( sqrt (k/m ) )
for a simple pendulum, T = 2*pi * sqrt (L/g)

The Attempt at a Solution


For spring with apple, if mass of the apple is m, spring constant is k, then
mg = kx (using force); combining this with f = 1/2*pi ( sqrt (k/m) ) gives:
f = 1/(2*pi) ( sqrt (g/L) )
For simple pendulum, I think we have T = 2*pi* sqrt (L/g)
So i think we should then have: 2*pi* sqrt (L/g ) = 1/2 (1/2*pi) * sqrt (g/L), i.e.
L = g/(8 * pi^2).
However this is wrong and I am not sure why. (I don't know what the right answer is either).
 
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Hint: When using this formula for the swinging spring/mass pendulum:
wayfarer said:
for a simple pendulum, T = 2*pi * sqrt (L/g)
How does L relate to the unstretched length of the spring?
 
x is only length increment not the whole lenght
 
Dear Doc Al,
I think I understand my mistake - that I took the stretched length of the spring, and not its unstretched length now. But I am still a bit confused, and don't understand how to relate the two together - could you please tell me how I could do that?
 
Imagine that the spring has some unstretched length L_0. When you add the mass of the apple, by how much does it stretch?
 
I know that but I meant, I am not sure which formula is applicable here.
I thought first that we could use formula:
A = sqrt ( x_0 ^2 + (v_0x)^2/w^2 )
but it seems like v_0x = 0, so this formula doesn't seem to help much (it seems to give wrong answer in this situation).
Perhaps Hooke's Law, F = -kx would be helpful, but I seemed to try that before, by thinking that maybe kx = mg and trying along those lines - which didn't seem to work either.
Perhaps i could use COnservation of energy to try this?
Trying that, i get, if L is stretched, l is unstretched length, then
mg(L-l ) = 1/2 k (L-l)^2
L = l + (2mg)/k
Is that correct?
 
Last edited:
wayfarer said:
I know that but I meant, I am not sure which formula is applicable here.
I thought first that we could use formula:
A = sqrt ( x_0 ^2 + (v_0x)^2/w^2 )
but it seems like v_0x = 0, so this formula doesn't seem to help much (it seems to give wrong answer in this situation).
I don't recognize that formula or what you're trying to do. All you need are the two formulas you started out with (plus Hooke's law):
wayfarer said:
For a normal spring, f = 1/2*pi ( sqrt (k/m ) )
This one gives you the frequency of the vertical SHM. And with the information given, you now know the frequency of the pendulum motion. (How does frequency relate to period?)
for a simple pendulum, T = 2*pi * sqrt (L/g)
Use this to find the length of the spring pendulum. How does that length relate to the unstretched length?
 

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