Find length of sides of quadrilateral; write equation

  • Thread starter David Dudek
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In summary: In fact, the only thing that is guaranteed is that each of the expressions will give you a different perimeter. Thanks for pointing that out.
  • #1
David Dudek
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Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

a) write an equation for the perimeter and simplify: that's easy, and done. This ends up as 3x+5

b) Find the length of all sides. Using the result from above, 3x+5 = -5/3, and would give one of the sides a -negative answer. I assume one cannot have a negative length?


Homework Equations



P = (7-x)+(x+2)+(2x-1)+(x-3)
=3x+5

x = -5/3?

The Attempt at a Solution



If x=-5/3, then;
P=(7-5/3)+(5/3+2)+(2x5/3-1)+(5/3-3)
=5 1/3 + 3 2/3 + 21/3 + -1 1/3
 
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  • #2
David Dudek said:

Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

a) write an equation for the perimeter and simplify: that's easy, and done. This ends up as 3x+5

That isn't an equation of anything. Nothing you have written so far is an equation because equations have an = sign and two sides.

b) Find the length of all sides. Using the result from above, 3x+5 = -5/3, and would give one of the sides a -negative answer. I assume one cannot have a negative length?


Homework Equations



P = (7-x)+(x+2)+(2x-1)+(x-3)
=3x+5

x = -5/3?

The Attempt at a Solution



If x=-5/3, then;
P=(7-5/3)+(5/3+2)+(2x5/3-1)+(5/3-3)
=5 1/3 + 3 2/3 + 21/3 + -1 1/3

I can't make sense of any of that. You need to find where the sides intersect (the vertices) and use the distance formula to calculate the perimeter.
 
  • #3
Hi,

thanks for taking the time to respond.

I have spent a couple of days looking at this problem and have just discovered that a vital bit of information was there the whole time: the perimeter is 23cm!

Problem solved.

Thanks
 
  • #4
David Dudek said:

Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

David Dudek said:
I have spent a couple of days looking at this problem and have just discovered that a vital bit of information was there the whole time: the perimeter is 23cm!

Problem solved.

Thanks

Really?? That's pretty amazing. Given that the expressions above all should have "y =" on their left sides, those lines don't even form a quadrilateral.
 

What is a quadrilateral?

A quadrilateral is a four-sided polygon with four angles.

What is the equation for finding the length of the sides of a quadrilateral?

The equation for finding the length of the sides of a quadrilateral is:
s1 + s2 + s3 + s4 = perimeter

What information do I need to find the length of the sides of a quadrilateral?

You will need the measurements of all four sides of the quadrilateral and the perimeter of the shape.

Can I use any shape to find the length of the sides of a quadrilateral?

No, the shape must have four sides and four angles to be considered a quadrilateral.

What units should I use when finding the length of the sides of a quadrilateral?

The units used for the length of the sides and perimeter should be consistent, such as all in inches or all in centimeters.

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