Find length of sides of quadrilateral; write equation

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Homework Help Overview

The discussion revolves around a problem involving a quadrilateral with sides expressed in terms of a variable x: (7-x), (x+2), (2x-1), and (x-3). Participants are tasked with writing an equation for the perimeter and subsequently finding the lengths of the sides.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the expression for the perimeter, simplifying it to 3x+5. There is a question about the validity of negative lengths resulting from the calculated value of x. Some participants express confusion about the nature of the equations presented and the implications for the quadrilateral's geometry.

Discussion Status

The conversation has seen various interpretations of the problem, with some participants questioning the setup and assumptions regarding the quadrilateral's dimensions. One participant claims to have found a missing piece of information regarding the perimeter, which they state resolves their issue, although others express skepticism about the validity of the expressions provided.

Contextual Notes

There is mention of a perimeter value of 23cm, which appears to be a critical piece of information that was previously overlooked. Additionally, there are concerns about the expressions not forming a valid quadrilateral.

David Dudek
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Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

a) write an equation for the perimeter and simplify: that's easy, and done. This ends up as 3x+5

b) Find the length of all sides. Using the result from above, 3x+5 = -5/3, and would give one of the sides a -negative answer. I assume one cannot have a negative length?


Homework Equations



P = (7-x)+(x+2)+(2x-1)+(x-3)
=3x+5

x = -5/3?

The Attempt at a Solution



If x=-5/3, then;
P=(7-5/3)+(5/3+2)+(2x5/3-1)+(5/3-3)
=5 1/3 + 3 2/3 + 21/3 + -1 1/3
 
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David Dudek said:

Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

a) write an equation for the perimeter and simplify: that's easy, and done. This ends up as 3x+5

That isn't an equation of anything. Nothing you have written so far is an equation because equations have an = sign and two sides.

b) Find the length of all sides. Using the result from above, 3x+5 = -5/3, and would give one of the sides a -negative answer. I assume one cannot have a negative length?


Homework Equations



P = (7-x)+(x+2)+(2x-1)+(x-3)
=3x+5

x = -5/3?

The Attempt at a Solution



If x=-5/3, then;
P=(7-5/3)+(5/3+2)+(2x5/3-1)+(5/3-3)
=5 1/3 + 3 2/3 + 21/3 + -1 1/3

I can't make sense of any of that. You need to find where the sides intersect (the vertices) and use the distance formula to calculate the perimeter.
 
Hi,

thanks for taking the time to respond.

I have spent a couple of days looking at this problem and have just discovered that a vital bit of information was there the whole time: the perimeter is 23cm!

Problem solved.

Thanks
 
David Dudek said:

Homework Statement



I have a seemingly simple question. I have a quadrilateral with sides (starting with the left side, moving clockwise):(7-x), (x+2), (2x-1), (x-3).

David Dudek said:
I have spent a couple of days looking at this problem and have just discovered that a vital bit of information was there the whole time: the perimeter is 23cm!

Problem solved.

Thanks

Really?? That's pretty amazing. Given that the expressions above all should have "y =" on their left sides, those lines don't even form a quadrilateral.
 

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