Find Limit of Function: Homework Statement, Equations & Solution

  • Thread starter Thread starter daveronan
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary

Homework Help Overview

The discussion revolves around finding the limit of the function lim w→∞ (1 + z/w)w, which involves concepts from calculus, specifically limits and potentially L'Hôpital's rule.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of L'Hôpital's rule and the form of the expression, noting it as infinity times zero. There are attempts to rearrange the expression into a suitable form for applying L'Hôpital's rule, and questions arise about the correctness of these attempts.

Discussion Status

The discussion is active, with participants sharing their attempts and questioning each other's methods. Some guidance has been provided regarding the need to rearrange the limit into an appropriate form for L'Hôpital's rule, but there is no explicit consensus on the solution yet.

Contextual Notes

Participants mention the importance of correctly applying the chain rule and the logarithmic transformation in their attempts, indicating that there may be nuances in the setup that are under consideration.

daveronan
Messages
13
Reaction score
0

Homework Statement


Find the limit of the following function

lim w→∞ (1 + z/w)w

Homework Equations





The Attempt at a Solution



lim w→∞ w ln(1 + z/w)

Not sure where to go next...

Thanks
 
Physics news on Phys.org
I've tried l'hospital's rule, but I don't think I'm any closer.
 
Can you show how you tried l'Hopital's rule? Because I tried it and it worked.
 
w/(1 + z/w) + 1/ln(1 +z/w)
 
I think I may have forgot the chain rule...
 
w ln(1 + z/w) has the form infinity*0. You'll want to arrange it into an infinity/infinity form before you do l'Hopital. Can you show how you tried to apply it?
 
Dick said:
w ln(1 + z/w) has the form infinity*0. You'll want to arrange it into an infinity/infinity form before you do l'Hopital. Can you show how you tried to apply it?

lim w→∞ w.ln(1/w*(w+z))
 
After l'Hopital I'm getting lim w → ∞ ( -z/(w+z) + ln(1 + z/w))

This doesn't seem to help, not unless I'm doing something stupid.
 
daveronan said:
lim w→∞ w.ln(1/w*(w+z))

That's still infinity*0. Try rearranging it into [itex]\frac{ln(1+\frac{z}{w})}{\frac{1}{w}}[/itex]. That's 0/0.
 
  • #10
daveronan said:
After l'Hopital I'm getting lim w → ∞ ( -z/(w+z) + ln(1 + z/w))

This doesn't seem to help, not unless I'm doing something stupid.

I've done that, but it still brings me to this.
 
  • #11
Wait, the penny dropped. The answer is z. You multiply across by -(w+z) :) Thanks for all your help.!
 
  • #12
... not forgetting you took the logarithm at the start.
 

Similar threads

Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K