A hydraulic jack has a pump piston of diameter 0.650cm, and a load piston of 4.40cm. Find the load which can be lifted if a force of 500.N is exerted on the pump piston.(adsbygoogle = window.adsbygoogle || []).push({});

Would you use the equation Fd=F(2)d(2)?

So (0.00650m)(500.N)=F(.0440m)

=73.9N

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# Homework Help: Find load with jack and piston

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