Find magnetic field at a distance from wire

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic field at a distance from a wire carrying a current with uniform density. The initial magnetic field at a distance of 1.25m from the wire is given as 2.55 μT, and the calculation for the magnetic field at a distance of 0.0065m involves using the equation B = (μ0I)/(2πr). The correct approach requires using the magnetic field equation for points inside the wire, resulting in B2 = (μ0Ir2)/(2πR2). The final calculated value for B2 is 4.9 x 10^-4 T.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with magnetic field equations
  • Knowledge of the permeability of free space (μ0)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of Ampère's Law
  • Learn about the magnetic field inside a conductor
  • Explore applications of magnetic fields in electrical engineering
  • Review the concept of current density in wires
USEFUL FOR

Students in physics or electrical engineering, particularly those studying electromagnetism and magnetic fields around conductors.

ooohffff
Messages
74
Reaction score
1

Homework Statement


A wire with radius R= .01 m carries a current with uniform density. At a distance r1 =1.25m from the wire, the magnetic field has a magnitude of 2.55 μT. Calculate the magnitude of the magnetic field r2=.0065m from the wire.

Homework Equations


B= (μ0I)/ 2πr

The Attempt at a Solution


So first I did:
B1=(μ0I)/( 2πr1)
Solving for I:
I = (B12πr1)/μ0
Plugging it into the B2 equation:
B2=(μ0B12πr1)/(2πr2μ0)
= (B1r1)/r2
=4.9 x 10^-4 T

I'm not sure if I did this right since other people in my class got something different. Can someone corroborate this? Thanks.
 
Physics news on Phys.org
Hello. Keep in mind that the equation B= (μ0I)/ (2πr) is only valid for points outside the wire.
 
TSny said:
Hello. Keep in mind that the equation B= (μ0I)/ (2πr) is only valid for points outside the wire.

Oh I see, I would have to use the equation for the magnetic field inside the wire for B2:

B2= (μ0Ir2)/ (2πR2)

Plugging I into this equation:
B2= (μ0B12πr1r2)/ (2πR2μ0)
=(B1r1r2)/ R2
 
That looks correct to me.
 

Similar threads

Replies
2
Views
1K
Replies
8
Views
2K
Replies
14
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
11
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
8
Views
2K