Find Magnetic Field of Infinite Slab with constant current density

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Homework Help Overview

The discussion revolves around finding the magnetic field generated by an infinite slab with a constant current density, specifically in the context of applying Ampere's Law. The problem involves understanding the geometry of the slab and the implications of the current density on the magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Ampere's Law, with attempts to evaluate line integrals and the current enclosed by the amperian loop. There are questions regarding the orientation of the sides of the rectangular prism used in the calculations and the implications of the current density on the magnetic field.

Discussion Status

Some participants are providing clarifications on the geometry and the direction of the magnetic field, while others express confusion about the calculations and notation used. There is an ongoing exploration of the correct approach to evaluating the integrals and understanding the setup of the problem.

Contextual Notes

Participants note the infinite extent of the slab in the x and y directions, with boundaries defined in the z direction. There are mentions of the need for clearer definitions and sketches to aid understanding of the problem setup and calculations.

datran
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Homework Statement


Find the magnetic field from an infinite slab with constant current density, Jo, in the x direction.

ρ(z) = ρ1 x_hat for -b<z<b
ρ(z) = 0 for |z| >= b


Homework Equations


Ampere's Law.

The Attempt at a Solution



I draw a rectangular prism inside the slab with -b<z<b with length 2z.

I use Ampere's Law for the 4 sides and two sides are 0 due to being perpendicular to the current density.

My remaining line integrals give me: 2zB + 2zB = μInet

Inet = Itotal (A of amperian loop / A total slab)
Inet = Itotal (2zxy / 2bxy)
Inet = Jo dot dS (z/b)

I do not know what to do with that integral of Jo dot dS.

Am I on the right track?

Thank you!
 
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The magnetic field is constant and [edit:] parallel to your sides, if you chose them properly. This allows to evaluate the integral.
 
Last edited:
I don't understand. I've already canceled two due to being perpendicular. Are you saying all 4 sides will be perpendicular?

I've already solved the left side of the Ampere's law. Are you saying the line integrals are wrong?
 
Sorry, that should be parallel.
Are you saying the line integrals are wrong?
I don't understand your notation.
 
I am given Jo, the current density.
Inet = Current enclosed by amperian loop
Itotal = Total current in slab.
the slab is infinite in x and y direction but stops at -b< z <b in z direction.
A is area of slab on XY plane
Itotal = integral of J DOT dS

I use ampere's law and create a rectangular prism inside the slab. Two of the lines are 0 due to being perpendicular. The other two with length 2z add up and become

4zB =μ (Inet)

Inet = Itotal (Volume of amperian Loop / Volume of Slab)
Inet = Itotal (2zA / 2bA)
Inet = integral J DOT dS (z/b)
Inet = integral Jo DOT dS (z/b)

I do not know if I am doing the right side correctly.

Thanks for the replies!
 
Can you add a sketch of your rectangle?

Itotal = Total current in slab.
A is area of slab on XY plane
Those are not well-defined.
 
z_hat points up. x_hat right. y_hat into the board. slab goes from -infinity< x and y < infinity

-b< z < b. I draw a ampere rectangular prism starting at the origin going to infinity in x and y direction. I go z1 up and -z1 down where -b < z1 < b.

I do the loop in one face since current is pointing in the +x_hat direction. Using Right hand rule, B is coming out in -y direction at z >= b and beyond. B is coming into the board at y_hat direction at z <= -b
 
You have a magnetic field in the slab as well, but that is not relevant here.
I understand the geometry of the problem statement, I just don't understand what you are trying to calculate.
 
I am trying to find the magnetic field in and outside of the slab.
 
  • #10
That is not what I meant. I did understand the problem statement based on the first post, there is no need to repeat.

Apparently you have made some attempt to solve it - but I have no idea what you did there, and I don't think this will change without a sketch or a very clear explanation how you came to those calculations.
If it involves any infinite length, current or whatever: This is wrong.
 
  • #11
I don't understand what you cannot follow. If I'm doing something wrong, I would love to be pointed in the right direction.

I calculated the line integral on the left side of Ampere's Law by calculating the rectangle where two sides cancel and the remaining sides are on the z axis. Since these sides are length 2z, they add up to be 4zB. I do not know how to calculate the right side.

You could throw a dog a bone and show me a little of what to do.
 

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