Find Mass and Speed given Tension and Angle

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SUMMARY

The discussion focuses on calculating the mass of a seat and its speed on a rotating amusement park ride, given the constants L (length of the chain), T (tension), and Theta (angle of the chain). The key equation utilized is F=mv²/r, where the radius r is derived from the geometry of the ride. The participants clarify the angle's orientation, emphasizing that it should be considered from the vertical perspective rather than horizontal. The solution requires expressing mass and speed in terms of the known constants without introducing variables that are not provided.

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  • Understanding of circular motion dynamics, specifically centripetal force.
  • Familiarity with trigonometric functions, particularly sine and cosine.
  • Knowledge of Newton's second law of motion, F=ma.
  • Basic algebraic manipulation skills to rearrange equations.
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  • Study the derivation of centripetal force in circular motion.
  • Learn how to apply trigonometric identities in physics problems.
  • Explore the relationship between tension, mass, and acceleration in rotating systems.
  • Investigate the effects of varying angles on the forces acting on objects in circular motion.
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geek96boolea10
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Homework Statement


Imagine one of those amusement park rides where you have a large rotating disc with seats hung by chains around it. As the disc spins, the seats also spin whilst rising up as well. The question asks for all answers to be written given the constants L, the length of the chain, T, the tension of the chain, and Theta, the angle above the horizontal that the chain is at. Given that the diameter of the disc is 2L, the chain is L, the angle is Theta, the tension between seat and disc is T, and the speed of rotation is constant, determine the mass of a seat and the speed of that seat.

Homework Equations


I'm pretty sure F=mv2/r is important. Lcos(theta) and Lsin(theta) are also useful in some way.

The Attempt at a Solution


My solution attempt was to simply expand F=mv2/r, replacing what I could. I ended up with the equation:
mv2 = T/(L+Lcos(theta)) which can be changed to m= or v2= pretty easily. However, they both include either m or v, which are not allowed since they aren't given constants. I'm sure that I've been using the wrong equation or that I'm missing some fundamental equality that would make this super easy - help!
 
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geek96boolea10 said:
and Theta, the angle above the horizontal that the chain is at
The angle above the horizontal? Do you mean the angle below the horizontal? (I just want to make sure we're imagining the same ride.)
 
geek96boolea10 said:
the angle above the horizontal that the chain is at
They won't be above the horizontal. Did you mean below horizontal, or maybe angle from vertical?
geek96boolea10 said:
I'm pretty sure F=mv2/r is important.
Yes, but what do v and r represent there in the context of this question?
 

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