Find mass of an object hanging on string

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To find the mass of an object hanging on a string, the relevant formula involves analyzing the forces acting on the masses. For two bodies A and B connected by a string over a pulley, the net force on mass B can be expressed as F_net = m_B * g - T = m_B * a, while for mass A, it is T - m_A * g = m_A * a. By eliminating the tension T from these equations, the relationship between the masses can be derived. Specifically, the formula α = (m_B - m_A) / (m_B + m_A) * g can be used to find mass B when given the acceleration and mass of A. Understanding the forces and applying Newton's second law is key to solving this problem.
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please tell me how to find the mass of an object which is hang on the string?
I mean what would be the formula ?
i am also writing here my numerical question...
Q:two bodies A and B are attached to a string which passes over a pulley so that two bodies hang vertically.if the mass of body A is 4.8 kg find the mass of body B which moves down with an acceleration of 0.2m/s.s.(g=9.8m/s.s)
 
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Make a diagram of the situation.

Look carefully at mass B. How many forces act on mass B?
 
no force is acting on mass B the formula given in our textbook is:
α=(mB-mA/mB+mA) x g

i don't know how to arrange it to find the mass B...:confused:
 
We are trying to show HOW to get that formula.

Look at mass B. It has the Earth pulling it down - that is the weight mB x g of mass b - and the string pulling it up by a tension T.

Now use Fnet = ma for mass B.
 
Fnet = ma ...for mass B

mBg - T = mBa

Fnet = ma ....for mass A

T - mAg = mAa

If the tension T is eliminated from the above two equations then one gets the equation required.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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