Find mass using acceleration and tension

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Homework Help Overview

The problem involves determining the mass of a box being raised with a known upward acceleration and tension in the rope. The context is centered around dynamics and forces acting on the box.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the importance of considering gravitational force. There are attempts to set up free-body diagrams and equate forces, but some express confusion about the relationships between tension, weight, and acceleration.

Discussion Status

There is an ongoing exploration of the correct approach to relate the forces acting on the box. Some participants suggest drawing diagrams and clarifying the net force, while others are questioning the assumptions made in their calculations. No consensus has been reached yet.

Contextual Notes

Participants note the significance of distinguishing between forces acting in different directions and the need for careful consideration of the free-body diagram. There is an acknowledgment that the acceleration is not a force, which may affect the interpretation of the problem.

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Homework Statement


A box is raised using a rope. If the acceleration of the box, is 5.2 m/s2 (upward) and the tension in the rope is 58 N, what is the mass of the box (in kg)?



Homework Equations





The Attempt at a Solution


I thought T=ma would work, but yeah, it didn't.
 
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Methinks you're forgetting the gravitational force.
 
The BEST FIRST STEP is DRAW A DIAGRAM with ALL the FORCES.
 
so. My FBD looks like:
T upwards with A
And Weight downwards, so mg.
so T+A = mg
but, that didn't work either
 
First, choose a proper set of coordinate axes(one +ve and other -ve) and then accordingly draw a free-body diagram.Finally,equate the NET force to ma .
Please take note that A or a is the acceleration and NOT a force .
 
I did draw that's what I just said.

" so. My FBD looks like:
T upwards with A
And Weight downwards, so mg.
so T+A = mg
but, that didn't work either "
 
Try using F(net) = ma (upwards)
 
grzz said:
Try using F(net) = ma (upwards)

Yes, use F(net) = m*a(up) = m*5.2 (as given in the problem). In addition, F(net) = the sum of all the forces acting on the box, which, as you said, is the tension (given as 58N) and the weight.
 
Note that Fnet is made up of two forces, the weight and the tension. But we want Fnet upwards. So one has to be careful what to put for Fnet because the weight is downwards but the tension is upwards. That is why THE FBD IS VERY IMPORTANT.
 

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