Find Min Value: $a,b,c>0$ with $a+b+c=k$

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Discussion Overview

The discussion centers around finding the minimum value of the expression $\sqrt{a^2+b^2}+\sqrt{b^2+c^2}+\sqrt{c^2+a^2}$ under the constraints that $a, b, c > 0$ and $a + b + c = k$. The scope includes mathematical reasoning and optimization techniques.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • Some participants present solutions to the problem, although the details of these solutions are not specified.
  • There is an expression of appreciation for one of the solutions, indicating that at least one proposed approach is well-received.
  • The problem is reiterated by another participant, suggesting a focus on the same mathematical challenge.

Areas of Agreement / Disagreement

The discussion does not show clear consensus, as multiple participants have proposed solutions without resolving which, if any, is definitive.

Contextual Notes

Details of the proposed solutions are not provided, leaving the discussion open to interpretation and further exploration of methods.

Albert1
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$a,b,c>0$

$a+b+c=k$

find:$min(\sqrt{a^2+b^2}+\sqrt{b^2+c^2}+\sqrt{c^2+a^2})$
 
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My Solution:

Given $$a+b+c = k$$ and $$a,b,c>0$$

Now we can write $$\sqrt{a^2+b^2} = \left|a+ib\right|$$ and $$\sqrt{b^2+c^2} = \left|b+ic\right|$$ and $$\sqrt{c^2+a^2} = \left|c+ia\right|$$

Where $$i=\sqrt{-1}$$ So Using Triangle Inequality of Complex number

$$\left|a+ib\right|+\left|b+ic\right|+\left|c+ia\right|\geq \left|\left(a+b+c\right)+i\left(b+c+a\right)\right| = \left|k+ik\right|=\sqrt{2}k$$

and equality hold when $$\displaystyle \frac{a}{b} = \frac{b}{c} = \frac{c}{a}$$
 
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jacks said:
My Solution:

Given $$a+b+c = k$$ and $$a,b,c>0$$

Now we can write $$\sqrt{a^2+b^2} = \left|a+ib\right|$$ and $$\sqrt{b^2+c^2} = \left|b+ic\right|$$ and $$\sqrt{c^2+a^2} = \left|c+ia\right|$$

Where $$i=\sqrt{-1}$$ So Using Triangle Inequality of Complex number

$$\left|a+ib\right|+\left|b+ic\right|+\left|c+ia\right|\geq \left|\left(a+b+c\right)+i\left(b+c+a\right)\right| = \left|k+ik\right|=\sqrt{2}k$$

and equality hold when $$\displaystyle \frac{a}{b} = \frac{b}{c} = \frac{c}{a}$$
nice solution !
 
Albert said:
$a,b,c>0$

$a+b+c=k$

find:$min(\sqrt{a^2+b^2}+\sqrt{b^2+c^2}+\sqrt{c^2+a^2})$
 

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