Find Minimal Polynomial for Matrix: Solution Help

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The minimal polynomial for the given matrix is m(t) = (t-2)^4, determined by the largest Jordan block size of 4. The unique monic polynomial of least degree that satisfies P(A) = 0 is confirmed by the calculation (A-2I)^4 = 0. While the suggested method is straightforward, alternative approaches using computer algebra systems like Maple can also be utilized for more complex cases. These methods involve treating powers of the matrix as vectors to find linear dependencies. The discussion emphasizes the importance of understanding Jordan forms in finding minimal polynomials.
cristina89
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Homework Statement


Given the matrix
2 0 0 0 0 0 0
1 2 0 0 0 0 0
0 1 2 0 0 0 0
0 0 1 2 0 0 0
0 0 0 0 2 0 0
0 0 0 0 1 2 0
0 0 0 0 0 0 2

What is the minimal polynomial?

Homework Equations



-

The Attempt at a Solution



This is the Jordan form, so I guess the solution is just m(t) = (t-2)7 but I don't know if it's right. Can anyone help me?
 
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cristina89 said:

Homework Statement


Given the matrix
2 0 0 0 0 0 0
1 2 0 0 0 0 0
0 1 2 0 0 0 0
0 0 1 2 0 0 0
0 0 0 0 2 0 0
0 0 0 0 1 2 0
0 0 0 0 0 0 2

What is the minimal polynomial?

Homework Equations



-

The Attempt at a Solution



This is the Jordan form, so I guess the solution is just m(t) = (t-2)7 but I don't know if it's right. Can anyone help me?

Hi cristina89! :smile:

The minimal polynomial P of a square matrix A is the unique monic polynomial of least degree, m, such that P(A) = 0.

The degree of the minimal polynomial is determined by the size of the largest Jordan block, which is 4 in your case.
So the minimal polynomial is m(t) = (t-2)4.

Indeed ##(A-2I)^4=0##.
 
Thank you so much! :)
 
cristina89 said:
Thank you so much! :)

The method suggested above is by far the simplest way to deal with this specific problem, but in a more general case you can use the algorithms employed by computer algebra systems, such as Maple: regard A, A^2, A^3,... as n^2-dimensional vectors, then find the smallest k such the vectors I, A, A^2,..,A^k are linearly dependent---essentially, using standard linear algebra methods. This will also deliver the coefficients and hence the minimal polynomial.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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