Find Mole % of N2H4 in Mixture: Homework Statement

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Discussion Overview

The discussion revolves around a homework problem involving a mixture of ammonia (NH3) and hydrazine (N2H4) in a sealed container, focusing on calculating the mole percent of N2H4 after both substances decompose under specific conditions. The problem involves concepts of gas laws, stoichiometry, and the relationships between initial and final pressures during the decomposition process.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about how to start solving the problem.
  • Another participant suggests expressing initial and final pressures as functions of the initial partial pressures of NH3 and N2H4.
  • It is proposed that the initial pressures can be represented as p0 = 0.5 x XNH3 and p1 = 0.5 x XN2H4, where XNH3 and XN2H4 are the mole fractions.
  • A participant questions the necessity of using moles, suggesting that molar fractions can be derived from total and partial pressures.
  • Clarification is provided that molar fraction and mole percent are essentially the same, just expressed differently.
  • Another participant mentions the need to find the final pressure after decomposition, noting the change in gases to N2 and H2.
  • It is suggested to find the ratio between initial and final moles using stoichiometry, emphasizing that the volume remains constant and that pressure relates directly to the number of moles.
  • A participant shares their approach, assuming moles of NH3 as 'a' and N2H4 as 'b', and derives relationships based on stoichiometry and gas laws, ultimately calculating the mole percent of N2H4 as 25%.

Areas of Agreement / Disagreement

The discussion includes multiple viewpoints on how to approach the problem, with participants providing different methods for expressing pressures and calculating mole fractions. There is no consensus on a single method, as participants explore various approaches to reach a solution.

Contextual Notes

Participants rely on assumptions about ideal gas behavior and stoichiometric relationships, but the discussion does not resolve potential limitations or dependencies on specific conditions or definitions.

Saitama
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Homework Statement


A mixture of NH3 and N2H4 is placed in a sealed container at 300K. The total pressure is 0.5atm. The container is heated to 1200K, when both substances decompose completely according to the equations,
2NH3--->N2+3H2
N2H4--->N2+2H2
After decomposition is complete, the total pressure at 1200K is found to be 4.5atm. Find the mole percent of N2H4 in the original mixture.


Homework Equations





The Attempt at a Solution


I am not getting any idea on how to start.
Please give me some ideas on beginning with it.

Thanks! :)
 
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Assume the initial partial pressures of both were p0 and p1.

Can you express both initial and final pressures as functions of p0 and p1?
 
Borek said:
Assume the initial partial pressures of both were p0 and p1.

Can you express both initial and final pressures as functions of p0 and p1?

I can express initial pressure like this:-
p0= 0.5 x XNH3
p1= 0.5 x XN2H4

XNH3--> mole fraction of NH3
XN2H4---->mole fraction of N2H4.

But i don't have the moles. :(
 
Why not p0 + p1 = 0.5 atm?

You don't need moles - you can express molar fraction using just total and partial pressures.
 
Borek said:
Why not p0 + p1 = 0.5 atm?

You don't need moles - you can express molar fraction using just total and partial pressures.

Yes, we can do p0+p1=0.5 atm.

But why then we need molar fraction here?
 
Molar fraction, mole percent - same thing, just expressed in slightly different way. That's what you have to calculate, aren't you?
 
Borek said:
Molar fraction, mole percent - same thing, just expressed in slightly different way. That's what you have to calculate, aren't you?

Yeah I have to calculate that.

I am having problems finding the final pressure. The gases has changed to N2 and H2. What should i do now?
 
You can find ratio between initial and final number of moles from the stoichiometry. A volume doesn't change, number of moles is directly related to the pressure.
 
Sorry Borek. I did not replied to this post for a long time. :)

I worked on your hints and they proved to be very useful. I was only stuck at the stoichiometric calculation which was the easiest part. :P

Here's how i solved it:-

I assumed moles of NH3 as 'a' and that of N2H4 as 'b'.

Then using stoichiometry i found the total moles of N2 as [itex]\frac{a+2b}{2}[/itex] and of H2 as [itex]\frac{3a+4b}{2}[/itex].

Before decomposition, using ideal gas equation:-
(0.5V)/(300R)=(a+b)

After decomposition, using ideal gas equation:-
(4.5V)/(1200R)=(2a+3b)

After solving, i get a=3b.

Mole fraction of N2H4= (b)/(a+b)=b/4b=0.25

Since we are asked to find mole percent, therefore 0.25*100=25%.

Thanks for the help Borek. :smile:
 

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